POWER SYSTEM ANALYSIS+DESIGN-EBK >I<
POWER SYSTEM ANALYSIS+DESIGN-EBK >I<
6th Edition
ISBN: 9781337259170
Author: Glover
Publisher: INTER CENG
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For the circuit shown, let V₁ = 12 V, Is1 = 2A, Is2 = 4A, R₁ = 2, R2 = 4, and R3 = 6. Determine the current Io using Mesh method as follows: 1. Choose all meshes that must be included, if any, to construct the supermesh. 11, 13 O 11, 12 O 12, 13, 11 12, 13 O none of the above 2. Consider mesh (loop) iz, write the corresponding expression in terms of mesh currents i₁, 12, 13 as of the form (R11 · i₁ + R₁2 · 2 + R₁3-13 = V₁), then enter the corresponding values: R11 R12 R13 Ω Ω Ω V V₁₂ 3. Solve the above equation to determine then lo : 10 = Ist A R₁ ww ww R₂ + V₁ 1, R3 The relative tolerance for this problem is 7%. ww IS2
Enter the matrix values (numerical) to solve for mesh-currents i₁, iz and 13, for the circuit shown, using Mesh method. In the matrix, row 1, row 2, and row 3 correspond to i₁, 12 and 13, current expressions, respectively. Let Vs=15, R₁ =50, R₂-32, R3-8, R4-17, R5-29, and R=41. [R11 R12 R13 The matrix values are shown here: R21 R22 R23 = V₂ R31 R32 R33 [V3] The relative tolerance for this problem is 5%. R1 Loop i₁ R11 + Vs Ω R12 Ω R13 Ω V V₁= Loop 12 R21 Ω R22 Ω R23 Ω V V₂ Loop 13 Ω R31 R32 Ω R33 Ω V3= V R2 R4 R3 R5 R6
For circuit shown, use Mesh method to find the voltage Vo as follows. Enter, in the matrix format, as below, the loop currents, where row 1, and row 2, correspond to i₁, and i2 loop current expressions, respectively. Let Vs1-5, Vs2-15, R₁=5, R₂=2, and R3=8. The matrix values are shown here: [R11 R12 21 R21 R22 Rx - M - M iz = The relative tolerance for this problem is 5%. Vst (+- R1 ww Loop i₁ R115 G12 V₁ = Loop 12 R21 R22 V₂= Ω C C Ω V Ω 02 C V R₂ ww VS2 + Ry ww + Vo Use Cramer's rule (matrix), substitution, or any other method to calculate the voltages:
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