FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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At steady state, a refrigeration cycle operating between hot and cold reservoirs at 300 K and 235 K, respectively, removes energy by heat transfer from the cold reservoir at a rate of 1000 kW.(a) If the cycle’s coefficient of performance is 4, determine the power input required, in kW.(b) Determine the minimum theoretical power required, in kW, for any such cycle
At steady state, a refrigeration cycle removes 800 kJ/min of energy by heat transfer from acold space maintained at -15o C and discharges energy by heat transfer to its surroundings at20o C. If the coefficient of performance of the actual cycle is 80 percent of that of areversible refrigeration cycle (ideal) operating between thermal reservoirs at these twotemperatures (β = 0.80 βmax), determine:a) Coefficient of performance;b) Power input to the cycle, in kW;c) Heat rejected to the surroundings.Draw sketch and show all calculations.
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- A reversible heat pump cycle operates at steady state between hot and cold reservoirs at TH = 30°C and Tc 10°C, respectively. The rate of heat transfer at the high temperature is 10 kW. a. Determine the net power input, in kW. b. Determine the heat transfer rate from the cold reservoir at Tc, in kW. c. Determine the coefficient of performance of the cycle.arrow_forwardAn air conditioner operating at steady state maintains a dwelling at 20 C on a day when the outside temperature is 35 C. Energy is removed by heat transfer from the dwelling at a rate of 2800 J/s while the air conditioner's power input is 0.8 kw. (a) Determine the coefficient of performance of the air conditioner. (b) Determine the power input required if it was a Carnot refrigerator. English (United States) 目 98%arrow_forwardA power cycle operates between hot and cold reservoirs at 500 K and 310 K. At steady state the cycle develops a power output of 0.1 MW. Determine the minimum theoretical rate at which energy is rejected by heat transfer to the cold reservoir in MW.arrow_forward
- Three sub steps of a thermodynamic cycle are employed in order to change the state of a gas from 1 bar, 1.5 cubic meter and internal energy of 512 kJ. The processes are: 1st step: Compression at constant PV to a pressure of 2 bar and internal energy of 690 kJ. 2nd step: A process where work transferred is zero and heat transferred is - 150 kJ. 3rd step: A process where work transferred is -50 kJ. without KE and PE changes, determine: a. heat transferred during 1st step (kJ) b. heat transferred during 3rd step (kJ)arrow_forwardBetween a heat source at temperature T and a low-temperature heat well at 280 K power cycle is working. In steady state, the cycle produces 50 kW of work, while the heat well is 1000 kl/min. heats up. Determine the minimum theoretical value for T in K (Kelvin).arrow_forwardProblem 1 - Refrigerator A refrigerator operates at steady state with a coefficient of performance of 4.5 and a power input of 0.8 kW. Energy is rejected from the refrigerator to the surroundings at 20°C by heat transfer from metal coils attached to the back. Determine (a) the rate energy is rejected, in kW. (b) the lowest theoretical temperature inside the refrigerator, in K.arrow_forward
- C5 6.arrow_forwardThe refrigerator shown in the figure below operates at steady state with a coefficient of performance (COP) of 5.0 within a kitchen at 23 °C. The refrigerator rejects 4.8 kW by heat transfer to its surroundings from metal coils located on its exterior. Determine: (a) the power input, in kW.(b) the lowest theoretical temperature inside the refrigerator, in K.arrow_forwardAn air conditioner is a device used to cool the inside of a home. It is, in essence, a refrigerator in which mechanical work is done and heat removed from the (cooler) inside and rejected to the (warmer) outside. A home air conditioner operating on a reversible Carnot cycle between the inside, absolute temperature T2, and the outside, absolute tempera- ture T1 > T2, consumes P joules/sec from the power lines when operating continuously. (a) In one second, the air conditioner absorbs Q2 joules from the house and rejects Q1 joules outdoors. Develop a formula for the efficiency ratio Q2/P in terms of T1 and T2. (b) Heat leakage into the house follows Newton's law Q = A(T, – T2). Develop a formula for T, in terms of T1, P, and A for continuous operation of the air conditioner under constant outside temperature T and uniform (in space) inside temperature T2. (c) The air conditioner is controlled by the usual on-off thermostat and it is observed that when the thermostat set at 20°C and an…arrow_forward
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