Loose Leaf For Introduction To Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259878084
Author: Smith Termodinamica En Ingenieria Quimica, J.m.; Van Ness, Hendrick C; Abbott, Michael; Swihart, Mark
Publisher: McGraw-Hill Education
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Chapter 5, Problem 5.33P
Interpretation Introduction
Interpretation:
The power requirement should be determined with
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PU + 9625
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Ternary Phase Diagram+ Material balance
Feed mixture weighing 200 kg of unknown composition containing water, acetic acid, isopropyl ether is
contacted in a single stage with 280kg mixture containing 40wt% acetic acid. 10wt% water and 50wt% isopropyl
ether. The resulting raffinate layer weight 320 kg and containing 29.5 wt% acetic acid, 66.5 wt% water and 4wt%
isopropyl ether. Determine the composition of the original feed mixture and the extract layer
Water layer
Isopropyl ether layer
acetic acid
0
water
98.8
Isopropyl ether
1.2
acetic acid
0
water
Isopropyl ether
0.6
99.4
0.69
98.1
1.2
0.18
0.5
99.3
1.41
97.1
1.5
0.37
0.7
98.9
2.89
95.5
1.6
0.79
0.8
98.4
6.42
91.7
1.9
1.93
1
97.1
13.3
84.4
2.3
4.82
1.9
93.3
25.5
71.1
3.4
11.4
3.9
84.7
36.7
58.9
4.4
21.6
6.9
71.5
44.3
5.1
10.6
31.1
10.8
58.5
46.4
37.1
16.5
36.2
15.1
48.7
Graphically+Material balance
2500 kg/hr of (20-80) nicotine water solution is to be extracted with benzene containing 0.5% nicotine in
the 1st and 2nd stages while the 3rd stage is free of nicotine. Cross-current operation is used with different amounts
of solvent for each stages 2000kg/hr in the 1st stage, 2300 kg/hr in the 2nd stage, 2600 kg/hr in the 3rd,
determine:-
a- The final raffinate concentration and % extraction.
b- b-The minimum amount of solvent required for counter-current operation if the minimum concentration
will be reduced to 5% in the outlet raffinate.
Equilibrium data
Wt % Nicotine in water
0
4
16
25
Wt % Nicotine in benzene
0
4
21
30
Chapter 5 Solutions
Loose Leaf For Introduction To Chemical Engineering Thermodynamics
Ch. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10P
Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - A flue gas is cooled from 2000 to 300( °F), and...Ch. 5 - Prob. 5.49PCh. 5 - Ethylene vapor is cooled at atmospheric pressure...
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- Feed mixture weighing 200 kg of unknown composition containing water, acetic acid, isopropyl ether is contacted in a single stage with 280kg mixture containing 40wt% acetic acid. 10wt% water and 50wt% isopropyl ether. The resulting raffinate layer weight 320 kg and containing 29.5wt% acetic acid, 66.5 wt% water and 4wt% isopropyl ether. Determine the composition of the original feed mixture and the extract layer Water layer Isopropyl ether layer acetic acid water Isopropyl ether acetic acid water Isopropyl ether 0 98.8 1.2 0 0.6 99.4 0.69 98.1 1.2 0.18 0.5 99.3 1.41 97.1 1.5 0.37 0.7 98.9 2.89 95.5 1.6 0.79 0.8 98.4 6.42 91.7 1.9 1.93 1 97.1 13.3 84.4 2.3 4.82 1.9 93.3 25.5 71.1 3.4 11.4 3.9 84.7 36.7 58.9 4.4 21.6 6.9 71.5 44.3 5.1 10.6 31.1 10.8 58.5 46.4 37.1 16.5 36.2 15.1 48.7arrow_forward2000 Kg/hr on an acetone water mixture containing 10% of acetone is to be extracted with trichloroethane. The recovered solvent to be used is free of acetone. If 95% recovery of acetone is desired, the equilibrium relationship is given by kg acetone/kg trichloroethane 1.65 kg acetone/kg water. Estimate the number of stages required if 1.5 times the minimum solvent is used when: - a- Cross-current is to be extracted. b- b- Counter-current is to be extracted.arrow_forward2/1000kg/h of an acetone - water mixture containing 20wt% by weight of acetone is to be counter currently extracted with trichloroethane. The recovered solvent to be used is free from acetone. The water and trichloroethane are insoluble. If 90% recovery of acetone is desired estimate the number of stages required if 1.5 times the minimum solvent is used. The kg acetone/kg extract=1.65 kg water/kg raffinate. a- Repeat the calculation of A if the solvent used has purity of 98.5%. b- If co-current extractor is used instead of counter-current extractor in A and B estimate the number of stages required if equal amount of solvent used in each stage.arrow_forward
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