Chemistry: An Atoms-Focused Approach
Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
Question
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Chapter 5, Problem 5.26QA
Interpretation Introduction

To find:

The molecular geometries of the given ions.

Expert Solution & Answer
Check Mark

Answer to Problem 5.26QA

Solution:

The molecular geometries of the ions are (a) linear, (b) tetrahedral, (c) linear, and (d) trigonal pyramidal.

Explanation of Solution

a) SCN-:

i. The Lewis structure:

The total number of valence electrons in a molecule of SCN- is 16.

Element Valence electrons
Symbol Number of atoms In one atom Total
S 1 6 1 x 6 = 6
C 1 4 1 x 4 = 4
N 1 5 1 x 5 = 5
Negative charge 1
Valence electrons in SCN- 16

C is the central atom because C is least electronegative atom. The Lewis structure of SCN- is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.

Chemistry: An Atoms-Focused Approach, Chapter 5, Problem 5.26QA , additional homework tip  1

Formula to calculate steric number SN =number of atoms bonded to central atom+Number of lone pairs on central atom

ii. In the Lewis structure there is one S and one N atom attached to central C atom having no lone pair of electrons. So SN = 2. There is a -1 formal charge on S atom

iii. For SN = 2 and as the bond angle is 180o, molecular geometry is linear.

b) CH3PCl3+:

i. The Lewis structure:

The total number of valence electrons in a molecule of CH3PCl3+ is 32.

Element Valence electrons
Symbol Number of atoms In one atom Total
C 1 4 1 x 4 = 4
H 3 1 3 x 1 = 3
P 1 5 1 x 5 = 5
Cl 3 7 3 x 7 = 21
Positive charge -1
Valence electrons in CH3PCl3+ 32

P is the central atom. The Lewis structure of CH3PCl3+ is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.

Chemistry: An Atoms-Focused Approach, Chapter 5, Problem 5.26QA , additional homework tip  2

ii. In the Lewis structure there are three chlorine atoms and one CH3 group via C atom bonded to central P atom. So SN = 4. There is +1 formal charge on three O atoms. So SN = 4.

iii. For SN = 4, the molecular geometry is tetrahedral and bond angle is 109.5o.

c) ICl2-:

i. The Lewis structure:

The total number of valence electrons in a molecule of ICl2- is 22.

Element Valence electrons
Symbol Number of atoms In one atom Total
I 1 7 1 x 7 = 7
Cl 2 7 2 x 7 = 14
Negative charge 1
Valence electrons in ICl2- 22

I is the central atom because I is least electronegative atom. The Lewis structure of ICl2- is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.

Chemistry: An Atoms-Focused Approach, Chapter 5, Problem 5.26QA , additional homework tip  3

ii. In the Lewis structure there are two oxygen atoms bonded to central I atom. There are three lone pair on I atom with -1 formal charge. So SN = 5.

iii. For SN = 5, the electron geometry is trigonal bipyramidal. As all lone pairs are at equatorial position to minimize the repulsion the molecular geometry is linear.

d) PO33-:

i. The Lewis structure:

The total number of valence electrons in a molecule of PO33- is 26.

Element Valence electrons
Symbol Number of atoms In one atom Total
P 1 5 1 x 5 = 5
O 3 6 3 x 6 = 18
Negative charge 3
Valence electrons in PO33- 26

P is the central atom because P is least electronegative atom. The Lewis structure of PO33- is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.

Chemistry: An Atoms-Focused Approach, Chapter 5, Problem 5.26QA , additional homework tip  4

ii. In the Lewis structure there are three O atoms bonded to central P atom. There is one lone pair on P atom. So SN = 4.

iii. If SN = 4, the electron geometry is tetrahedral but as there is one lone pair on P atom and it is bonded to three O atoms the geometry is trigonal pyramidal.

Conclusion:

The molecular geometries of the ions are (a) linear, (b) tetrahedral, (c) linear, and (d) trigonal pyramidal.

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Chapter 5 Solutions

Chemistry: An Atoms-Focused Approach

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