
To find:
The molecular geometries of the given ions.

Answer to Problem 5.26QA
Solution:
The molecular geometries of the ions are (a) linear, (b) tetrahedral, (c) linear, and (d) trigonal pyramidal.
Explanation of Solution
a) SCN-:
i. The Lewis structure:
The total number of valence electrons in a molecule of SCN- is 16.
Element | Valence electrons | ||
Symbol | In one atom | Total | |
S | 1 | 6 | 1 x 6 = 6 |
C | 1 | 4 | 1 x 4 = 4 |
N | 1 | 5 | 1 x 5 = 5 |
Negative charge | 1 | ||
Valence electrons in SCN- | 16 |
C is the central atom because C is least electronegative atom. The Lewis structure of SCN- is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.
Formula to calculate steric number SN
ii. In the Lewis structure there is one S and one N atom attached to central C atom having no lone pair of electrons. So SN = 2. There is a -1 formal charge on S atom
iii. For SN = 2 and as the bond angle is 180o, molecular geometry is linear.
b) CH3PCl3+:
i. The Lewis structure:
The total number of valence electrons in a molecule of CH3PCl3+ is 32.
Element | Valence electrons | ||
Symbol | Number of atoms | In one atom | Total |
C | 1 | 4 | 1 x 4 = 4 |
H | 3 | 1 | 3 x 1 = 3 |
P | 1 | 5 | 1 x 5 = 5 |
Cl | 3 | 7 | 3 x 7 = 21 |
Positive charge | -1 | ||
Valence electrons in CH3PCl3+ | 32 |
P is the central atom. The Lewis structure of CH3PCl3+ is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.
ii. In the Lewis structure there are three chlorine atoms and one CH3 group via C atom bonded to central P atom. So SN = 4. There is +1 formal charge on three O atoms. So SN = 4.
iii. For SN = 4, the molecular geometry is tetrahedral and bond angle is 109.5o.
c) ICl2-:
i. The Lewis structure:
The total number of valence electrons in a molecule of ICl2- is 22.
Element | Valence electrons | ||
Symbol | Number of atoms | In one atom | Total |
I | 1 | 7 | 1 x 7 = 7 |
Cl | 2 | 7 | 2 x 7 = 14 |
Negative charge | 1 | ||
Valence electrons in ICl2- | 22 |
I is the central atom because I is least electronegative atom. The Lewis structure of ICl2- is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.
ii. In the Lewis structure there are two oxygen atoms bonded to central I atom. There are three lone pair on I atom with -1 formal charge. So SN = 5.
iii. For SN = 5, the electron geometry is trigonal bipyramidal. As all lone pairs are at equatorial position to minimize the repulsion the molecular geometry is linear.
d) PO33-:
i. The Lewis structure:
The total number of valence electrons in a molecule of PO33- is 26.
Element | Valence electrons | ||
Symbol | Number of atoms | In one atom | Total |
P | 1 | 5 | 1 x 5 = 5 |
O | 3 | 6 | 3 x 6 = 18 |
Negative charge | 3 | ||
Valence electrons in PO33- | 26 |
P is the central atom because P is least electronegative atom. The Lewis structure of PO33- is drawn by completing the octet of each element present in the molecule by adding lone pairs on it.
ii. In the Lewis structure there are three O atoms bonded to central P atom. There is one lone pair on P atom. So SN = 4.
iii. If SN = 4, the electron geometry is tetrahedral but as there is one lone pair on P atom and it is bonded to three O atoms the geometry is trigonal pyramidal.
Conclusion:
The molecular geometries of the ions are (a) linear, (b) tetrahedral, (c) linear, and (d) trigonal pyramidal.
Want to see more full solutions like this?
Chapter 5 Solutions
Chemistry: An Atoms-Focused Approach
- For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forward
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
- give example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward
- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





