FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
error_outline
This textbook solution is under construction.
Students have asked these similar questions
2. A power cycle receives energy QH by heat transfer from a hot reservoir at TH = 1200 R and rejects energy QC by heat transfer to a cold reservoir at TC = 400 R. For each of the following cases, determine whether the cycle operates reversibly, operates irreversibly, or is impossible.
(a) QH = 900 Btu, Wcycle = 450 Btu
(b) QH = 900 Btu, QC = 300 Btu
(c) Wcycle = 600 Btu, QC = 400 Btu
(d) Eff. = 70%
A power cycle operating at steady state receives energy by heat transfer at a rate Q at TH = 1800 Kand rejects energy by heat
transfer to a cold reservoir at a rate Oc at Tc = 600K. For each of the following cases, determine whether the cycle operates
reversibly, operates irreversibly, or is impossible.
(a) Qu = (500) kW, Oc = (100) kW
%3D
(b) Qu = (500)kW, Wey
cycle
(250)kW, Oc = (200)kW
(c) Weycle = (350)kW, Oc = (150)kW
(d) On = (500)kw, Oc = (100)kW
A power cycle operating at steady state receives energy by heat transfer at a rate QH at TH = 1800 K and rejects energy by heat
transfer to a cold reservoir at a rate Qc at Tc = 600 K. For each of the following cases, determine whether the cycle operates
reversibly, operates irreversibly, or is impossible.
(a) Qu
(300) kW, Oc = (100) kW
(b) QH
(500)kW, Wcycle =
(150)kW, Oc = (200)kW
(c) Wcycle
(450)kW, Oc
= (150)kW
(d) QH = (500)kW, Oc = (100)kW
Knowledge Booster
Similar questions
- At steady state, a reversible heat pump cycle discharges energy at the rate QH to a hot reservoir at temperature TH, while receiving energy at the rate Oc from a cold reservoir at temperature Tc. (a) If TH = 16°C and Tc = 2°C, determine the coefficient of performance. (b) If OH = 20 kW, Oc = 8.75 kW, and Tc= 0°C, determine TH, in °C. (c) If the coefficient of performance is 20 and TH = 27°C, determine Tc, in °C.arrow_forwardNeed ASAP thank youuarrow_forwardA power cycle operating at steady state receives energy by heat transfer at a rate Q at T = 1800 K and rejects energy by heat transfer to a cold reservoir at a rate Qc at Tc = 600 K. For each of the following cases, determine whether the cycle operates reversibly, operates irreversibly, or is impossible. (a) Q₁ = (300) kW, Qc Part A (b) Qu = (500)kW, W cycle = (150) kW, Qc = (200)KW (c) W cycle = (350) kW, Qc = (150) kW (d) Qu = (500)kW, Qc = (100)kW = The cycle is (100) kW Determine whether the cycle operates reversibly, operates irreversibly, or is impossible. QH = 300kW, Qc = 100kW Save for Later Attempts: 0 of 5 used Part B The parts of this question must be completed in order. This part will be available when you complete the part above. Part C The parts of this question must be completed in order. This part will be available when you complete the part above. Part D The parts of this question must be completed in order. This part will be available when you complete the part above.…arrow_forward
- A power cycle operating between two reservoirs receives energy QH by heat transfer from a hot reservoir at TH = 2000 K and rejects energy Qc by heat transfer to a cold reservoir at Tc= 400 K. For each of the following cases determine whether the cycle operates reversibly, irreversibly, or does not verify the second law of thermodynamics (make all necessary calculation for each case). a) QH= 1200 kJ and Wcycle = 1020 kJ b) QH= 1200 kJ and Qc = 240 kJ c) Wcycle = 1020 kJ and Qc = 600 kJ d) n =40%arrow_forwardTwo reversible power cycles are arranged in series. The first cycle receives energy by heat transfer from a reservoir at temperature TH and rejects energy to a reservoir at an intermediate temperature T. The second cycle receives the energy rejected by the first cycle from the reservoir at temperature T and rejects energy to a reservoir at temperature TC lower than T. Derive an expression for the intermediate temperature T in terms of TH and TC when,a. The net works of the two power cycles are equalb. The thermal efficiencies of the two power cycles are equalarrow_forwardThermodynamics Iarrow_forward
- At steady state, a refrigeration cycle removes 800 kJ/min of energy by heat transfer from acold space maintained at -15o C and discharges energy by heat transfer to its surroundings at20o C. If the coefficient of performance of the actual cycle is 80 percent of that of areversible refrigeration cycle (ideal) operating between thermal reservoirs at these twotemperatures (β = 0.80 βmax), determine:a) Coefficient of performance;b) Power input to the cycle, in kW;c) Heat rejected to the surroundings.Draw sketch and show all calculations.arrow_forwardAt steady state, a reversible heat pump cycle discharges energy at the rate Q˙H to a hot reservoir at temperature TH, while receiving energy at the rate Q˙C from a cold reservoir at temperature TC.(a) If TH = 10°C and TC = 2°C, determine the coefficient of performance.(b) If Q˙H= 15 kW, Q˙C= 8.75 kW, and TC = 0°C, determine TH, in °C.(c) If the coefficient of performance is 5 and TH = 27°C, determine TC, in °C.arrow_forwardThree sub steps of a thermodynamic cycle are employed in order to change the state of a gas from 1 bar, 1.5 cubic meter and internal energy of 512 kJ. The processes are: 1st step: Compression at constant PV to a pressure of 2 bar and internal energy of 690 kJ. 2nd step: A process where work transferred is zero and heat transferred is - 150 kJ. 3rd step: A process where work transferred is -50 kJ. without KE and PE changes, determine: a. heat transferred during 1st step (kJ) b. heat transferred during 3rd step (kJ)arrow_forward
- As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1500°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy QC by heat transfer to a reservoir at TC = 450°R. All energy transfers are positive in the directions of the arrows. Determine:(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1500°R and 450°R, respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle.arrow_forward7. A power cycle operating between two thermal reservoirs receives energy QH by heat transfer from a hot reservoir at TH = 1600 K and rejects energy QC by heat transfer to a cold reservoir at TC = 400 K. For each of the following cases determine whether the cycle operates reversibly, operates irreversibly, or is impossible. a. QH = 1000 kJ, ŋ = 75% b. QH = 1100 kJ, Wcycle = 800 kJ c. QH = 900 kJ, QC = 300 kJarrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Tc = 500°R. All energy transfers are positive in the directions of the arrows. Determine: Hot reservoir at TH QH Reservoir at T R1 lo ali R2 Qc Cold reservoir at Te W. cycle W cycle (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R. respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY