Essentials Of Materials Science And Engineering
Essentials Of Materials Science And Engineering
4th Edition
ISBN: 9781337385497
Author: WRIGHT, Wendelin J.
Publisher: Cengage,
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Chapter 5, Problem 5.16P
Interpretation Introduction

Interpretation:

The reason for the energy of activation for diffusion through the interstitial mechanism to be lower than that for another mechanism needs to be explained.

Concept introduction:

The institutional mechanism is the mechanism in which an atom is smaller and requires less energy to pass the surrounding atom.

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One thousand kg/h of a (50-50 wt%) acetone-in-water solution is to be extracted at 25C in a continuous, countercurrent system with pure 1,1,2-trichloroethane to obtain a raffinate containing 10 wt% acetone. Using the following equilibrium data, determine with an equilateral-triangle diagram: a- the minimum flow rate of solvent; b- the number of stages required for a solvent rate equal to 1.5 times minimum, and composition of each streamleaving each stage. c- Repeat the calculation of (a) and (b) if the solvent used has purity 93wt% (4wr% acetone, 3wt% water impurities) acetone water 1,1,2-trichloroethane Raffinate. Weight Extract. Weight 0.6 0.13 0.27 Fraction Acetone Fraction Acetone 0.5 0.04 0.46 0.44 0.56 0.4 0.03 0.57 0.29 0.40 0.3 0.02 0.68 0.12 0.18 0.2 0.015 0.785 0.0 0.0 0.1 0.01 0.89 0.55 0.35 0.1 0.5 0.43 0.07 0.4 0.57 0.03 0.3 0.68 0.02 0.2 0.79 0.01 0.1 0.895 0.005
2500 kg/hr of (20-80) nicotine water solution is to be extracted with benzene containing 0.5% nicotine in the 1st and 2ed stages while the 3rd stage is free of nicotine. Cross- current operation is used with different amounts of solvent for each stages 2000kg/hr in the 1st stage, 2300 kg/hr in the 2nd stage, 2600 kg/hr in the 3rd, determine: - a- The final raffinate concentration and % extraction. b- b- The minimum amount of solvent required for counter-current operation if the minimum concentration will be reduced to 5% in the outlet raffinate. Equilibrium data Wt % Nicotine in water Wt % Nicotine in benzene 0 4 16 25 0 4 21 30
2000 Kg/hr on an acetone water mixture containing 10% of acetone is to be extracted with trichloroethane. The recovered solvent to be used is free of acetone. If 95% recovery of acetone is desired, the equilibrium relationship is given by kg acetone/kg trichloroethane 1.65 kg acetone/kg water. Estimate the number of stages required if 1.5 times the minimum solvent is used when: - a- Cross-current is to be extracted. b- b- Counter-current is to be extracted.

Chapter 5 Solutions

Essentials Of Materials Science And Engineering

Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. 5.48PCh. 5 - Prob. 5.49PCh. 5 - Prob. 5.50PCh. 5 - Prob. 5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. 5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67PCh. 5 - Prob. 5.68PCh. 5 - Prob. 5.69PCh. 5 - Prob. 5.70PCh. 5 - Prob. 5.71PCh. 5 - Prob. 5.72PCh. 5 - Prob. 5.73PCh. 5 - Prob. 5.74PCh. 5 - Prob. 5.75PCh. 5 - Prob. 5.76PCh. 5 - Prob. 5.77PCh. 5 - Prob. 5.78PCh. 5 - Prob. 5.79PCh. 5 - Prob. 5.80PCh. 5 - Prob. 5.81DPCh. 5 - Prob. 5.82DPCh. 5 - Prob. 5.83DPCh. 5 - Prob. 5.84DPCh. 5 - Prob. 5.85DPCh. 5 - Prob. 5.86CPCh. 5 - Prob. 5.87CPCh. 5 - Prob. 5.88CPCh. 5 - Prob. K5.1KP
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