Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393600681
Author: Gilbert
Publisher: W. W. Norton & Company
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Chapter 5, Problem 5.13QA
Interpretation Introduction
To find:
Why NO3- and NO2- ions have similar O—N—O bond angles even though they have different numbers of N—O bonds.
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Calculate equilibrium concentrations for the following reaction:N2 (g) + O2 (g) ⇋ 2 NO (g) Kc = 0.10 at 2273K initially [N2] = 0.200M; [O2] = 0.200
For each scenario below, select the color of the solution using the indicator thymol blue during the titration.
When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] .
At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] .
When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] .
When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color is
Chapter 5 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 5 - Prob. 5.1VPCh. 5 - Prob. 5.2VPCh. 5 - Prob. 5.3VPCh. 5 - Prob. 5.4VPCh. 5 - Prob. 5.5VPCh. 5 - Prob. 5.6VPCh. 5 - Prob. 5.7VPCh. 5 - Prob. 5.8VPCh. 5 - Prob. 5.9VPCh. 5 - Prob. 5.10VP
Ch. 5 - Prob. 5.11QACh. 5 - Prob. 5.12QACh. 5 - Prob. 5.13QACh. 5 - Prob. 5.14QACh. 5 - Prob. 5.15QACh. 5 - Prob. 5.16QACh. 5 - Prob. 5.17QACh. 5 - Prob. 5.18QACh. 5 - Prob. 5.19QACh. 5 - Prob. 5.20QACh. 5 - Prob. 5.21QACh. 5 - Prob. 5.22QACh. 5 - Prob. 5.23QACh. 5 - Prob. 5.24QACh. 5 - Prob. 5.25QACh. 5 - Prob. 5.26QACh. 5 - Prob. 5.27QACh. 5 - Prob. 5.28QACh. 5 - Prob. 5.29QACh. 5 - Prob. 5.30QACh. 5 - Prob. 5.31QACh. 5 - Prob. 5.32QACh. 5 - Prob. 5.33QACh. 5 - Prob. 5.34QACh. 5 - Prob. 5.35QACh. 5 - Prob. 5.36QACh. 5 - Prob. 5.37QACh. 5 - Prob. 5.38QACh. 5 - Prob. 5.39QACh. 5 - Prob. 5.40QACh. 5 - Prob. 5.41QACh. 5 - Prob. 5.42QACh. 5 - Prob. 5.43QACh. 5 - Prob. 5.44QACh. 5 - Prob. 5.45QACh. 5 - Prob. 5.46QACh. 5 - Prob. 5.47QACh. 5 - Prob. 5.48QACh. 5 - Prob. 5.49QACh. 5 - Prob. 5.50QACh. 5 - Prob. 5.51QACh. 5 - Prob. 5.52QACh. 5 - Prob. 5.54QACh. 5 - Prob. 5.55QACh. 5 - Prob. 5.56QACh. 5 - Prob. 5.57QACh. 5 - Prob. 5.58QACh. 5 - Prob. 5.59QACh. 5 - Prob. 5.60QACh. 5 - Prob. 5.61QACh. 5 - Prob. 5.62QACh. 5 - Prob. 5.63QACh. 5 - Prob. 5.64QACh. 5 - Prob. 5.65QACh. 5 - Prob. 5.66QACh. 5 - Prob. 5.67QACh. 5 - Prob. 5.68QACh. 5 - Prob. 5.69QACh. 5 - Prob. 5.70QACh. 5 - Prob. 5.71QACh. 5 - Prob. 5.72QACh. 5 - Prob. 5.73QACh. 5 - Prob. 5.74QACh. 5 - Prob. 5.75QACh. 5 - Prob. 5.76QACh. 5 - Prob. 5.77QACh. 5 - Prob. 5.78QACh. 5 - Prob. 5.79QACh. 5 - Prob. 5.80QACh. 5 - Prob. 5.81QACh. 5 - Prob. 5.82QACh. 5 - Prob. 5.83QACh. 5 - Prob. 5.84QACh. 5 - Prob. 5.85QACh. 5 - Prob. 5.86QACh. 5 - Prob. 5.87QACh. 5 - Prob. 5.88QACh. 5 - Prob. 5.89QACh. 5 - Prob. 5.90QACh. 5 - Prob. 5.91QACh. 5 - Prob. 5.92QACh. 5 - Prob. 5.93QACh. 5 - Prob. 5.94QACh. 5 - Prob. 5.95QACh. 5 - Prob. 5.96QACh. 5 - Prob. 5.97QACh. 5 - Prob. 5.98QACh. 5 - Prob. 5.99QACh. 5 - Prob. 5.100QACh. 5 - Prob. 5.101QACh. 5 - Prob. 5.102QACh. 5 - Prob. 5.103QACh. 5 - Prob. 5.104QACh. 5 - Prob. 5.105QACh. 5 - Prob. 5.106QACh. 5 - Prob. 5.107QACh. 5 - Prob. 5.108QACh. 5 - Prob. 5.109QACh. 5 - Prob. 5.110QACh. 5 - Prob. 5.111QACh. 5 - Prob. 5.112QACh. 5 - Prob. 5.113QACh. 5 - Prob. 5.114QACh. 5 - Prob. 5.115QACh. 5 - Prob. 5.116QACh. 5 - Prob. 5.117QACh. 5 - Prob. 5.118QACh. 5 - Prob. 5.119QACh. 5 - Prob. 5.120QACh. 5 - Prob. 5.121QACh. 5 - Prob. 5.122QACh. 5 - Prob. 5.123QACh. 5 - Prob. 5.124QACh. 5 - Prob. 5.125QACh. 5 - Prob. 5.126QACh. 5 - Prob. 5.127QACh. 5 - Prob. 5.128QACh. 5 - Prob. 5.129QACh. 5 - Prob. 5.130QACh. 5 - Prob. 5.131QACh. 5 - Prob. 5.132QA
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- The following reaction is run in which the initial conditions include only methane (CH4) at a concentration of0.115 M. Once equilibrium was established, the concentration of acetylene (C2H2) was measured to be 0.035M. What is the value of the equilibrium constant, K?2 CH4 (g) ⇋ C2H2 (g) + 3 H2 (g)arrow_forwardCalculate the equilibrium concentration of carbon dioxide for the following reaction:2 COF2 (g) ⇋ CF4 (g) + CO2 (g) Kc = 2.00 at 10.00 °C. at equilibrium [COF2] = 0.255M; [CF4] = 0.118Marrow_forwardIn a benzene derivative that has -CH2CH3, indicate how it can be substituted by -COOH.arrow_forward
- In a sulfonated derivative of benzene, indicate how -SO3H can be eliminated.arrow_forwardWhat is the equilibrium expression (law of mass action) for the following reaction:CO2 (g) + H2O (l) ⇋ H+ (aq) + HCO3- (aq)arrow_forwardIndicate the compound resulting from adding NaOH cyclopentane-CH2-CHO.arrow_forward
- Use the provided information to calculate Kc for the following reaction at 550 °C: H2(g) + CO2(g) ⇌ CO(g) + H2O(g) Kc = ?CoO(s) + CO(g) ⇌ Co(s) + CO2(g) Kc1 = 490CoO(s) + H2(g) ⇌ Co(s) + H2O(g) Kc2 = 67arrow_forwardCalculate Kc for the reaction: I2 (g) ⇋ 2 I (g) Kp = 6.26 x 10-22 at 298Karrow_forwardFor each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forward
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