FUNDAMENTALS OF THERMODYNAMICS
10th Edition
ISBN: 9781119634928
Author: Borgnakke
Publisher: WILEY
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As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives
energy QH by heat transfer from a hot reservoir at TH-1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate
temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by
heat transfer to a reservoir at Te - 500°R. All energy transfers are positive in the directions of the arrows.
Determine:
Hot reservoir at TH
lH
R1
Reservoir Q
at T
20
R2
lc
Cold reservoir at Tc
We
cycle
W
Wcycle
(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.
(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R,
respectively. Also, determine the ratio of the network developed by the single cycle to the network developed by each of the two
cycles, Wcycle-
Need ASAP thank you.
4. What is the second law of thermodynamics, give its Clausius and Kelvin-Planck statements
and justify on their basis why a perpetual motion machines that extracts heat from ambient
environment to do work is not feasible. What is difference between reversible and an internally
reversible process, and why are most actual processes considered irreversible.
Numerical:
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- One kg of fluid expands reversibly according to a linear law from 4.2 bar to 1.4 bar. The initial and final volume are 0.004 and 0.02 m² respectively. The fluid then cooled reversibly at constant pressure, and finally compressed reversibly according to a law PV=C back to initial condition of 4.2 bar and 0.004 m². Calculate the work done for each process, the net work done and sketch the cycle on the P-V diagram. (4480, -1120, -1845 &1515 N-m)arrow_forwardQ2 In a system, 90 kJ of heat is supplied from state 1 to state 2 by constant volume process. The internal energy at state 1 is 100 kJ. The system rejects 105 kJ of heat from state 2 to state 3 by constant pressure process and 40 kJ of work is done on it. The system is brought back from state 3 to state 1 by a reversible adiabatic process. Calculate the adiabatic work and the values of internal energy at state 2 and state 3arrow_forward4.31 A refrigerator using R-134a as the refrigerant is used to keep a space at -10°C by rejecting heat to ambient air at 22 °C. R-134a enters the compressor at 140 kPa as a saturated vapor and leaves at 800 kPa and 70°C. The refrigerant leaves the condenser as a saturated liquid. The rate of cooling provided by the system is 2600 W. Determine (a) the mass flow rate of R-134a, (b) the COP, (c) the exergy destruction in each component of the cycle, (d) the second-law efficiency of the cycle, and (e) the total exergy destruction in the cycle.arrow_forward
- Referring to the reversible heat pump cycle shown in the figure, p1 = 14.7 Ib/in?, p4 = 20.3 lb/in?, v1 = 12.6 ft°/lb, v4 = 10.0 ft³/lb, and the gas is air obeying the ideal gas model. p4 pi V4 Determine TH, in °R, and the coefficient of performance.arrow_forwardPLEASE ANSWER THIS QUESTION ASAP!!!arrow_forwardQ2: Source 1 can supply energy at the rate of 12000 kJ/min at 320°C. A second source 2 can supply energy at the rate of 120000 kJ/min at 70°C. Which source (1 or 2) would you choose to supply energy to an ideal reversible heat engine that is to produce large amount of power if the temperature of the surroundings is 35°C?arrow_forward
- 5.45 WP As shown in Fig. P5.45, an air conditioner operating at steady state maintains a dwelling at 70°F on a day when the outside temperature is 90°F. If the rate of heat transfer into the dwelling through the walls and roof is 30,000 Btu/h, might a net power input to the air conditioner compressor of 3 hp be sufficient? If yes, determine the coefficient of performance. If no, determine the minimum theoretical power input, in hp.arrow_forwardP5.38arrow_forwardAn air conditioner is a device used to cool the inside of a home. It is, in essence, a refrigerator in which mechanical work is done and heat removed from the (cooler) inside and rejected to the (warmer) outside. A home air conditioner operating on a reversible Carnot cycle between the inside, absolute temperature T2, and the outside, absolute tempera- ture T1 > T2, consumes P joules/sec from the power lines when operating continuously. (a) In one second, the air conditioner absorbs Q2 joules from the house and rejects Q1 joules outdoors. Develop a formula for the efficiency ratio Q2/P in terms of T1 and T2. (b) Heat leakage into the house follows Newton's law Q = A(T, – T2). Develop a formula for T, in terms of T1, P, and A for continuous operation of the air conditioner under constant outside temperature T and uniform (in space) inside temperature T2. (c) The air conditioner is controlled by the usual on-off thermostat and it is observed that when the thermostat set at 20°C and an…arrow_forward
- Find the mean effective pressure of the thermodynamic cycle shown in the figure below.arrow_forwardTwo reversible cycles are in series, each process doing the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at 1000°R and energy Q is reinjected by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and reinjects the QC energy by heat transfer to the reservoir at a temperature of 400°R. All energy transferred is positive in the direction of the arrow. Determine: a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two cycles; b) the thermal efficiency of a simple reversible cycle operating between the hot and cold reservoirs at 1000°R and 400°C, respectively. Then determine the net work done by the simple cycle, expressed in terms of the net work done by each of the two cycles, Wcycle.arrow_forwardHeat engine and refrigerator. Consider a heat engine operating between temperatures Th and Tj. During each cycle with time At, work W is extracted, so Pout = W/At. (a) Assuming the processes are all reversible, what is the efficiency of this heat engine, n = Wout/Qn? (b) Now assume that the low temperature of the heat engine is lowered by a reversible refrigerator, such that the heat engine operates between Th and T. The refrigerator takes input power Pin = Win/At and operates between T and T, where Ti < T. Draw an energy- entropy flow diagram. (c) Calculate the net efficiency (Wout - Win)/Qh. Is the efficiency of this system higher, lower, or the same as your answer for (a)?arrow_forward
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