Explanation The given length is 2.4375 in.. The gauge block combination that produces the given length is obtained as follows. Step 1: To get 5 in the target length 2.4375 in., choose the block that has 5 in the fourth decimal place from the 36-block set and perform the operations as follows: Since it can be observed that the only block with 5 in the fourth decimal place is 0.0505, choose the block 0.0505. Subtract 0.0505 from 2.4375: 2.4375 in . ← The target length − 0.0505 in . _ ← The first block 2 .3870 in . ← The remainder Thus, the first block and the remainder obtained is 0.0505 and 2.3870, respectively. Set 2.387 in. as the new target length. Step 2 : To get 7 in the new target length 2.387 in., choose the block that has 7 in the third decimal place from the 36-block set and perform the operations as follows: Since it can be observed that the only block with 7 in the third decimal place is 0.057, choose the block 0.057. Subtract 0.057 from 2.3870: 2.387 in . ← The new target length − 0.057 in . _ ← The second block 2 .330 in . ← The remainder Thus, the second block and the remainder obtained is 0.057 and 2.330, respectively. Set 2.33 in. as the new target length. Step 3 : To get 3 in the new target length 2.33 in., choose the block that has 3 in the second decimal place from the 36-block set and perform the operations as follows: Since it can be observed that the only block with 3 in the third decimal place is 0.130, choose the block 0.130. Subtract 0.13 in. from 2.33 in.: 2

10th Edition

ISBN: 9780100803053

Author: SAUNDERS

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Chapter 5, Problem 4FPS

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The gauge block combination for testing the gap of width 2.4375 in..

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