
Business Driven Information Systems
6th Edition
ISBN: 9781260004717
Author: Paige Baltzan
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 5, Problem 4CCO
To determine
To Explain:
Apply the concepts of cloud computing to Etsy’s business model.
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A cylindrical container of internal diameter and height H =200 mm is filled with concrete asshown in the figure below. Beginning at room temperature (T = 20oC), the temperature isdecreased until the concrete develops internal tensile stress that may results in crack (as shown inthe figure on the right below). This is due to the thermal shrinkage of the concrete and strongadhesion between the concrete and the walls of the container. D = 100 mmDetermine the temperature at which the concrete develops a tensile crack.Hint: Assume that the concrete remains linearly elastic until failure.Information about concrete:E = 30 GPa (Young’s Modulus)ν = 0.2 (Poisson’s Ratio)α = 12 ·10-6mm/mm/ oC (Coefficient of thermal expansion)(σt)max = 3 MPa (tensile strength)
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1- Present worth analysis
An Environmental engineer is considering two materials for use in a sustainable
building. All estimates are made below. (a) Which should be selected on the basis
of a present worth comparison at an interest rate of 12% per year? (b) At what
first cost for the material not selected above will it become the more economical
alternative?
يفكر مهندس بيئة في الاختيار بين مادتين لاستخدامهما في انشاء مبنى مستدام كافة البيانات
الاقتصادية الخاصة بالمادتين مذكورة في الجدول ادناه.
(أ) أي المادتين ستختار على أساس مقارنة القيمة الحالية ) present worth analysis) اذا كان
معدل الفائدة 12% سنويًا؟
(ب) كم يجب ان تصبح الكلفة الاولية رأس المال) للمادة غير المختارة أعلاه لتصبح البديل الافضل
اقتصاديا؟
Material A
First Cost
15000
Maintenance cost
9000
Salvage value
2000
Life
5
Material B
35000
7000
20000
5
2- IRR analysis
A manufacturer of hydraulic equipment is trying to determine whether it should
use monoflange double block and bleed (DBB) valves or a multi-valve system
(MVS) for…
Chapter 5 Solutions
Business Driven Information Systems
Ch. 5 - Prob. 1OCQCh. 5 - Prob. 2OCQCh. 5 - Prob. 3OCQCh. 5 - Prob. 4OCQCh. 5 - Prob. 5OCQCh. 5 - Prob. 6OCQCh. 5 - Prob. 1RQCh. 5 - Prob. 2RQCh. 5 - Prob. 3RQCh. 5 - Prob. 4RQ
Ch. 5 - Prob. 5RQCh. 5 - Prob. 6RQCh. 5 - Prob. 7RQCh. 5 - Prob. 8RQCh. 5 - Prob. 9RQCh. 5 - Prob. 10RQCh. 5 - Prob. 11RQCh. 5 - Prob. 12RQCh. 5 - Prob. 13RQCh. 5 - Prob. 14RQCh. 5 - Prob. 15RQCh. 5 - Prob. 16RQCh. 5 - Prob. 1CCOCh. 5 - Prob. 2CCOCh. 5 - Prob. 3CCOCh. 5 - Prob. 4CCOCh. 5 - Prob. 5CCOCh. 5 - Prob. 1CCTCh. 5 - Prob. 2CCTCh. 5 - Prob. 3CCTCh. 5 - Prob. 1CBTCh. 5 - Prob. 2CBTCh. 5 - Prob. 3CBTCh. 5 - Prob. 4CBTCh. 5 - Prob. 5CBTCh. 5 - Prob. 6CBTCh. 5 - Prob. 7CBTCh. 5 - Prob. 8CBTCh. 5 - Prob. PIAYKBPCh. 5 - Prob. PIIAYKBPCh. 5 - Prob. PIIIAYKBPCh. 5 - Prob. PIVAYKBPCh. 5 - Prob. PVAYKBPCh. 5 - Prob. PVIAYKBPCh. 5 - Prob. PVIIAYKBPCh. 5 - Prob. PVIIIAYKBPCh. 5 - Prob. PXIAYKBPCh. 5 - Prob. PXAYKBP
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