EBK ENHANCED DISCOVERING COMPUTERS & MI
EBK ENHANCED DISCOVERING COMPUTERS & MI
1st Edition
ISBN: 9780100606920
Author: Vermaat
Publisher: YUZU
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Chapter 5, Problem 48SG
Program Plan Intro

Content filtering:

The content filtering is the use of software to filter or limit the access rights for certain materials or contents.

  • The content filtering is used by certain organizations to limit the web access from employees.

Web filtering:

Web filtering is the use of software to limit or filter the access rights for particular websites.

  • The web filter is used by certain organizations to limit or filter chat rooms, email messages, and so on.

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Exercise 1 Function and Structure [30 pts] Please debug the following program and answer the following questions. There is a cycle in a linked list if some node in the list can be reached again by continuously following the next pointer. #include typedef struct node { int value; struct node *next; } node; int 11_has_cycle (node *first) if (first == node *head = { NULL) return 0; first; while (head->next != NULL) { } if (head first) { return 1; } head = head->next; return 0; void test ll_has_cycle () { int i; node nodes [6]; for (i = 0; i < 6; i++) { nodes [i] .next = NULL; nodes [i].value = i; } nodes [0] .next = &nodes [1]; nodes [1] .next = &nodes [2]; nodes [2] .next = &nodes [3]; nodes [3] .next nodes [4] .next &nodes [4]; NULL; nodes [5] .next = &nodes [0]; printf("1. Checking first list for cycles. \n Function 11_has_cycle says it has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no"); printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle says it has %s…
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Chapter 5 Solutions

EBK ENHANCED DISCOVERING COMPUTERS & MI

Ch. 5 - Prob. 11SGCh. 5 - Prob. 12SGCh. 5 - Prob. 13SGCh. 5 - Prob. 14SGCh. 5 - Prob. 15SGCh. 5 - Prob. 16SGCh. 5 - Prob. 17SGCh. 5 - Prob. 18SGCh. 5 - Prob. 19SGCh. 5 - Prob. 20SGCh. 5 - Prob. 21SGCh. 5 - Prob. 22SGCh. 5 - Prob. 23SGCh. 5 - Prob. 24SGCh. 5 - Prob. 25SGCh. 5 - Prob. 26SGCh. 5 - Prob. 27SGCh. 5 - Prob. 28SGCh. 5 - Prob. 29SGCh. 5 - Prob. 30SGCh. 5 - Prob. 31SGCh. 5 - Prob. 32SGCh. 5 - Prob. 33SGCh. 5 - Prob. 34SGCh. 5 - Prob. 35SGCh. 5 - Prob. 36SGCh. 5 - Prob. 37SGCh. 5 - Prob. 38SGCh. 5 - Prob. 39SGCh. 5 - Prob. 40SGCh. 5 - Prob. 41SGCh. 5 - Prob. 42SGCh. 5 - Prob. 43SGCh. 5 - Prob. 44SGCh. 5 - Prob. 45SGCh. 5 - Prob. 46SGCh. 5 - Prob. 47SGCh. 5 - Prob. 48SGCh. 5 - Prob. 49SGCh. 5 - Prob. 1TFCh. 5 - Prob. 2TFCh. 5 - Prob. 3TFCh. 5 - Prob. 4TFCh. 5 - Prob. 5TFCh. 5 - Prob. 6TFCh. 5 - Prob. 7TFCh. 5 - Prob. 8TFCh. 5 - Prob. 9TFCh. 5 - Prob. 10TFCh. 5 - Prob. 11TFCh. 5 - Prob. 12TFCh. 5 - Prob. 1MCCh. 5 - Prob. 2MCCh. 5 - Prob. 3MCCh. 5 - Prob. 4MCCh. 5 - Prob. 5MCCh. 5 - Prob. 6MCCh. 5 - Prob. 7MCCh. 5 - Prob. 8MCCh. 5 - Prob. 1MCh. 5 - Prob. 2MCh. 5 - Prob. 3MCh. 5 - Prob. 4MCh. 5 - Prob. 5MCh. 5 - Prob. 6MCh. 5 - Prob. 7MCh. 5 - Prob. 8MCh. 5 - Prob. 9MCh. 5 - Prob. 10MCh. 5 - Prob. 2CTCh. 5 - Prob. 3CTCh. 5 - Prob. 4CTCh. 5 - Prob. 5CTCh. 5 - Prob. 6CTCh. 5 - Prob. 7CTCh. 5 - Prob. 8CTCh. 5 - Prob. 9CTCh. 5 - Prob. 10CTCh. 5 - Prob. 11CTCh. 5 - Prob. 12CTCh. 5 - Prob. 13CTCh. 5 - Prob. 14CTCh. 5 - Prob. 15CTCh. 5 - Prob. 16CTCh. 5 - Prob. 17CTCh. 5 - Prob. 18CTCh. 5 - Prob. 19CTCh. 5 - Prob. 20CTCh. 5 - Prob. 21CTCh. 5 - Prob. 22CTCh. 5 - Prob. 23CTCh. 5 - Prob. 24CTCh. 5 - Prob. 25CTCh. 5 - Prob. 26CTCh. 5 - Prob. 27CTCh. 5 - Prob. 28CTCh. 5 - Prob. 29CTCh. 5 - Prob. 1PSCh. 5 - Prob. 2PSCh. 5 - Prob. 3PSCh. 5 - Prob. 4PSCh. 5 - Prob. 5PSCh. 5 - Prob. 6PSCh. 5 - Prob. 7PSCh. 5 - Prob. 8PSCh. 5 - Prob. 9PSCh. 5 - Prob. 10PSCh. 5 - Prob. 11PSCh. 5 - Prob. 1.1ECh. 5 - Prob. 1.2ECh. 5 - Prob. 1.3ECh. 5 - Prob. 2.1ECh. 5 - Prob. 2.2ECh. 5 - Prob. 2.3ECh. 5 - Prob. 3.3ECh. 5 - Prob. 4.1ECh. 5 - Prob. 4.2ECh. 5 - Prob. 4.3ECh. 5 - Prob. 5.1ECh. 5 - Prob. 5.2ECh. 5 - Prob. 5.3ECh. 5 - Prob. 1IRCh. 5 - Prob. 2IRCh. 5 - Prob. 3IRCh. 5 - Prob. 4IRCh. 5 - Prob. 5IRCh. 5 - Prob. 1CTQCh. 5 - Prob. 2CTQCh. 5 - Prob. 3CTQCh. 5 - Prob. 4CTQ
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