Electric Circuits. (11th Edition)
11th Edition
ISBN: 9780134746968
Author: James W. Nilsson, Susan Riedel
Publisher: PEARSON
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Chapter 5, Problem 47P
a.
To determine
Find the expression for
b.
To determine
Find the value of
c.
To determine
Find the value of
d.
To determine
Find the value of open-loop gain
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I need help adding a capacitor and a Zener diode to my circuit. I’m looking for a simple sketch or diagram showing how to connect them. i want diagram with final circuit after adding the zener diad and capacitor. don't do calclution or anything. thanks
Question 3 AC Motor Drives [15]Calculate the instantaneous currents delivered by the inverter if the direct axiscurrent required at a particular instant is 8.66A and the quadrature current is5A. Derive all equations for the three currents.
A certain signal f(t) has the following PSD (assume 12 load):
Sp (w) = new + 8(w) - 1.5) + (w + 1.5)]
(a) What is the mean power in the bandwidth w≤2 rad/see?
(b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec?
Paress(w) dw
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Chapter 5 Solutions
Electric Circuits. (11th Edition)
Ch. 5.2 - Assume that the op amp in the circuit shown is...Ch. 5.3 - The source voltage vs in the circuit in Assessment...Ch. 5.4 - Find vo in the circuit shown if va = 0.1 V and vb...Ch. 5.5 - Assume that the op amp in the circuit shown is...Ch. 5.6 - In the difference amplifier shown, vb = 4.0 V....Ch. 5.6 - Suppose the 12kΩ resistor Rd in the difference...Ch. 5.7 - The inverting amplifier in the circuit shown has...Ch. 5 - The op amp in the circuit in Fig. P5.1 is ideal....Ch. 5 - Replace the 2.5 V source in the circuit in Fig....Ch. 5 - Find io in the circuit in Fig. P5.3 if the op amp...
Ch. 5 - The op amp in the circuit in Fig. P5.4 is...Ch. 5 - The op amp in the circuit in Fig. P5.5 is ideal....Ch. 5 - Find iL (in milliamperes) in the circuit in Fig....Ch. 5 - Prob. 7PCh. 5 - Design an inverting amplifier with a gain of 2.5,...Ch. 5 - Design an inverting amplifier with a gain of 4....Ch. 5 - The op amp in the circuit in Fig. P5.10 is...Ch. 5 - The op amp in the circuit shown in Fig. P5.11 is...Ch. 5 - The op amp in Fig. P5.12 is ideal.
What circuit...Ch. 5 - Design an inverting-summing amplifier using a 120...Ch. 5 - Prob. 14PCh. 5 - Design an inverting-summing amplifier so...Ch. 5 - The op amp in Fig. P5.16 is ideal. Find vo if va –...Ch. 5 - Prob. 17PCh. 5 - The op amp in the circuit of Fig. P5.18 is...Ch. 5 - Prob. 19PCh. 5 - The op amp in the circuit shown in Fig. P5.20 is...Ch. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - The op amp in the circuit of Fig. P5.23 is...Ch. 5 - The circuit in Fig. P5.24 is a noninverting...Ch. 5 - The op amp in the circuit of Fig. P5.25 is...Ch. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Select the values of Rb and Rf in the circuit in...Ch. 5 - The op amp in the adder-subtracter circuit shown...Ch. 5 - In the difference amplifier shown in Fig. P5.32,...Ch. 5 - Prob. 33PCh. 5 - The op amp in the circuit of Fig. P5.34 is...Ch. 5 - Assume that the ideal op amp in the circuit seen...Ch. 5 - Prob. 37PCh. 5 - Show that when the ideal op amp in Fig. P5.38 is...Ch. 5 - The op amps in the circuit in Fig. P5.39 are...Ch. 5 - The two op amps in the circuit in Fig. P5.40 are...Ch. 5 - The circuit inside the shaded area in Fig. P5.41...Ch. 5 - Assume that the ideal op amp in the circuit in...Ch. 5 - Derive Eq. 5.31.
(5.31)
Ch. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Repeat Problem 5.45 assuming an ideal op...Ch. 5 - Assume the input resistance of the op amp in Fig....Ch. 5 - Prob. 48PCh. 5 - Suppose the strain gages in the bridge in Fig....Ch. 5 - For the circuit shown in Fig. P5.50, show that if...Ch. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53P
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- (75 Marks) JA signal (t) is bond 7)(t)(t) and f(t), are band-limited to 1.2 kHz each. These signals are to be limited to 9.6 kHz, and three other signals transmitted by means of time-division multiplexing. Set up scheme for accomplishing this multiplexing requirement, with each signal sampled at its Nyquist rate. What must be the speed of the commutator (the output but ram-k bit/sec)? the minimum band width? (25 Marks)arrow_forwardDraw the digital modulation outputs, ASK Amplitude Shift Keying) FSK (Frequency Shift Keying) and PSK (Phase Shift Keying). For baseband and carriet frequency as shown 101 wwwwwwwwwwww 010 BASESAND basband CARRIER Carralarrow_forwardplease show full working. I've included the solutionarrow_forward
- can you please show working and steps. The answer is 8kohms.arrow_forwardPSD A certain signal f(t) has the following PSD (assume 12 load): | Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)] (a) What is the mean power in the bandwidth w≤ 1 rad/sec? (b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec? (c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec? (d) What is the total mean power in (t)? Pav= + 2T SfLw) dw - SALW)arrow_forwardAn AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forward
- Can you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forward
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