a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Question

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Answer 1

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.

With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin

Answer 2

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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Answer 3

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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See solution

Answer 5

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 6

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Answer 7

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Answer 8

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Answer 9

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Answer 10

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Answer 11

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Answer 12

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Answer 13

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Answer 14

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Answer 15

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Answer 16

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 17

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

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Answer 21

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a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Solution Summary: The author analyzes the results obtained from mating mutant strains with wild-type Neurospora. One mutant gene is responsible for trp - phenotype.

Concept explainers

Videos

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Want to see the full answer?

Chapter 5 Solutions

a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Solution Summary: The author analyzes the results obtained from mating mutant strains with wild-type Neurospora. One mutant gene is responsible for trp - phenotype.

Concept explainers

Videos

a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora. Introduction: In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b. To determine: The conclusions that can be drawn by the results obtained from mating mutant strains. Introduction: Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp- phenotype results from one mutant gene.

d. To draw: The genetic map that can provide a suitable explaination for the given data. Introduction: The cross between trp1 and trp2 can be represented as follows: trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e. To determine: The reason that the given case does not present the mating in the table as ordered octads. Introduction: First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f. To determine: The reason that the distance between gene and centromere can be observed from crosses given in the table. Introduction: SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Want to see the full answer?

Chapter 5 Solutions

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.