(a) A block with a mass m is pulled along a horizontal surface for a distance x by a constant force F → at an angle θ with respect to the horizontal. The coefficient of kinetic friction between block and table is μ k the force exerted by friction equal to μ k mg ? If not, what is the force exerted by friction? (b) How much work is done by the friction force and by F → ? (Don’t forget the signs.) (c) Identify all the forces that do no work on the block, (d) Let m = 2.00 kg, x = 4.00 m, θ = 37.0°, F = 15.0 N, and μ k = 0.400, and find I the answers to parts (a) and (b). Figure P5.39
(a) A block with a mass m is pulled along a horizontal surface for a distance x by a constant force F → at an angle θ with respect to the horizontal. The coefficient of kinetic friction between block and table is μ k the force exerted by friction equal to μ k mg ? If not, what is the force exerted by friction? (b) How much work is done by the friction force and by F → ? (Don’t forget the signs.) (c) Identify all the forces that do no work on the block, (d) Let m = 2.00 kg, x = 4.00 m, θ = 37.0°, F = 15.0 N, and μ k = 0.400, and find I the answers to parts (a) and (b). Figure P5.39
Solution Summary: The author explains the force exerted by friction and the work done by applied force.
(a) A block with a mass m is pulled along a horizontal surface for a distance x by a constant force
F
→
at an angle θ with respect to the horizontal. The coefficient of kinetic friction between block and table is μk the force exerted by friction equal to μkmg? If not, what is the force exerted by friction? (b) How much work is done by the friction force and by
F
→
? (Don’t forget the signs.) (c) Identify all the forces that do no work on the block, (d) Let m = 2.00 kg, x = 4.00 m, θ = 37.0°, F= 15.0 N, and μk = 0.400, and find I the answers to parts (a) and (b).
Figure P5.39
Definition Definition Force that opposes motion when the surface of one item rubs against the surface of another. The unit of force of friction is same as the unit of force.
Please solve and answer this problem correctly please. Thank you!!
You're on an interplanetary mission, in an orbit around the Sun. Suppose you make a maneuver that brings your perihelion in closer to the Sun but leaves your aphelion unchanged. Then you must have
Question 2 options:
sped up at perihelion
sped up at aphelion
slowed down at perihelion
slowed down at aphelion
The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
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