Concept explainers
What is each compound’s systematic name?
(a)
![Check Mark](/static/check-mark.png)
Interpretation:
Systematic name of the given compound should be determined.
Concept introduction:
- IUPAC name consists of three parts in major namely Prefix suffix and root word.
- Prefix represents the substituent present in the molecule and its position in the root name.
- Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
- For alkenes, suffix will be ‘ene’.
- Root word represents the longest continuous carbon skeleton of the organic molecule.
- When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
Answer to Problem 39P
Systematic name for given molecule is
Explanation of Solution
The structure of given compound is,
This reveals that the molecule contains a nine carbon chain with a double bond on the fourth carbon atom and two bromo groups on the third and eighth carbon atom respectively.
Therefore,
According with the IUPAC conventions the systematic name of the compound is,
(b)
![Check Mark](/static/check-mark.png)
Interpretation:
Systematic name of the given compound should be determined.
Concept introduction:
- IUPAC name consists of three parts in major namely Prefix suffix and root word.
- Prefix represents the substituent present in the molecule and its position in the root name.
- Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
- For alkenes, suffix will be ‘ene’.
- Root word represents the longest continuous carbon skeleton of the organic molecule.
- When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
- E-Z designators are used as like cis-trans terminology for non-similar groups attached alkenes.
- In E-Z designations, the groups attached to vinylic positions are checked by their priority on the basis of higher molecular weight. If the higher priority groups are on the same sides, then the configuration is designated as Z. If the higher priority groups are on the opposite sides, then the configuration is designated as E.
Answer to Problem 39P
Systematic name of the given compound is
Explanation of Solution
Given,
Compound is,
This reveals that the longest chain in the molecule contains eight carbon atoms with a double bond on third carbon atom and an ethyl group attached on the fourth carbon atom.
Two methyl groups were attached on the third and seventh carbon atom.
Therefore,
The systematic name of the compound is
(c)
![Check Mark](/static/check-mark.png)
Interpretation:
Systematic name of the given compound should be determined.
Concept introduction:
- IUPAC name consists of three parts in major namely Prefix suffix and root word.
- Prefix represents the substituent present in the molecule and its position in the root name.
- Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
- For alkenes, suffix will be ‘ene’.
- Root word represents the longest continuous carbon skeleton of the organic molecule.
- When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
Answer to Problem 39P
Systematic name of the compound is
Explanation of Solution
Given,
The structure of the compound is,
Structure of the compound reveals that that the given compound contains five membered carbon chain with double bond and on the first and fifth carbon atom methyl groups were attached.
Therefore,
The systematic name of the compound in accordance with IUPAC is,
(d)
![Check Mark](/static/check-mark.png)
Interpretation:
Systematic name of the given compound should be determined.
Concept introduction:
- IUPAC name consists of three parts in major namely Prefix suffix and root word.
- Prefix represents the substituent present in the molecule and its position in the root name.
- Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
- For alkenes, suffix will be ‘ene’.
- Root word represents the longest continuous carbon skeleton of the organic molecule.
- When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
- E-Z designators are used as like cis-trans terminology for non-similar groups attached alkenes.
- In E-Z designations, the groups attached to vinylic positions are checked by their priority on the basis of higher molecular weight. If the higher priority groups are on the same sides, then the configuration is designated as Z. If the higher priority groups are on the opposite sides, then the configuration is designated as E.
Answer to Problem 39P
Systematic name of the given compound is
Explanation of Solution
Given,
Structure of the compound is,
The structure of the compound reveals the molecule contains seven membered carbon chain with a double bond on the second carbon. On the third and second carbon atoms one ethyl and methyl group were attached.
Therefore the systematic name of the compound is
(e)
![Check Mark](/static/check-mark.png)
Interpretation:
Systematic name of the given compound should be determined.
Concept introduction:
- IUPAC name consists of three parts in major namely Prefix suffix and root word.
- Prefix represents the substituent present in the molecule and its position in the root name.
- Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
- For alkenes, suffix will be ‘ene’.
- Root word represents the longest continuous carbon skeleton of the organic molecule.
- When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
Answer to Problem 39P
Systematic name of the compound is
Explanation of Solution
Given,
The struicture of the compound is,
Structure of the compound reveals that that the given compound contains six membered carbon chain with double bond and on the fourth carbon atom one methyl group was attached.
Therefore,
The systematic name of the compound in accordance with IUPAC is,
4-methylcyclohexene.
(f)
![Check Mark](/static/check-mark.png)
Interpretation:
Systematic name of the given compound should be determined.
Concept introduction:
- IUPAC name consists of three parts in major namely Prefix suffix and root word.
- Prefix represents the substituent present in the molecule and its position in the root name.
- Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
- For alkenes, suffix will be ‘ene’.
- Root word represents the longest continuous carbon skeleton of the organic molecule.
- When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
Answer to Problem 39P
Systematic name of the given compound
Explanation of Solution
Given,
The structure of the compound is,
Structure of the compound reveals that that the given compound contains six membered carbon chain with double bond and on the fourth and fifth carbon atoms one ethyl and methyl group was attached respectively.
Therefore,
The systematic name of the compound in accordance with IUPAC’s rules and regulations is,
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Chapter 5 Solutions
CHEM 262 ORG CHEM EBOOK DIGITAL DELIVERY
- Please correct answer and don't use hand ratingarrow_forwardSafari File Edit View History Bookmarks Window Help く < mylabmastering.pearson.com Wed Feb 12 8:44 PM ✩ + Apple Q Bing Google SignOutOptions M Question 36 - Lab HW BI... P Pearson MyLab and Mast... P Course Home Error | bartleby b Answered: If the biosynth... Draw a free-radical mechanism for the following reaction, forming the major monobromination product: ScreenPal - 2022 CHEM2... Access Pearson 2 CH3 Br-Br CH H3 Draw all missing reactants and/or products in the appropriate boxes by placing atoms on the canvas and connecting them with bonds. Add charges where needed. Electron- flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical. ▸ View Available Hint(s) 0 2 DE [1] H EXP. CONT. H. Br-Br H FEB 12arrow_forwardPlease correct answer and don't use hand ratingarrow_forwardNonearrow_forwardQ1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. + CI Br : Н OH H wo་ཡིག་ཐrow HO 3 D ။။ဂ CI Br H, CI Br Br H₂N OMe R IN I I N S H Br ជ័យ CI CI D OHarrow_forwardPlease correct answer and don't use hand ratingarrow_forwardNonearrow_forward%Reflectance 95 90- 85 22 00 89 60 55 50 70 65 75 80 50- 45 40 WA 35 30- 25 20- 4000 3500 Date: Thu Feb 06 17:21:21 2025 (GMT-05:0(UnknownD Scans: 8 Resolution: 2.000 3000 2500 Wavenumbers (cm-1) 100- 2981.77 1734.25 2000 1500 1000 1372.09 1108.01 2359.09 1469.82 1181.94 1145.20 1017.01 958.45 886.97 820.49 668.25 630.05 611.37arrow_forwardNonearrow_forwardCH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forwardDraw the correct ionic form(s) of arginine at the pKa and PI in your titration curve. Use your titration curve to help you determine which form(s) to draw out.arrow_forwardPlease correct answer and don't use hand ratingarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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