Let ( a 1 a 2 a 3 a 4 ) and ( a 5 a 6 ) be disjoint cycles in S 10 . Show that there isno element x in S 10 such that x 2 = ( a 1 a 2 a 3 a 4 ) ( a 5 a 6 ) .
Let ( a 1 a 2 a 3 a 4 ) and ( a 5 a 6 ) be disjoint cycles in S 10 . Show that there isno element x in S 10 such that x 2 = ( a 1 a 2 a 3 a 4 ) ( a 5 a 6 ) .
Solution Summary: The author explains that there is no element x in S_10 such that x2=left, which is a disjoint product of 4-cycles.
Let
(
a
1
a
2
a
3
a
4
)
and
(
a
5
a
6
)
be disjoint cycles in
S
10
. Show that there isno element x in
S
10
such that
x
2
=
(
a
1
a
2
a
3
a
4
)
(
a
5
a
6
)
.
Problem #5
Suppose you flip a two sided fair coin ("heads" or "tails") 8 total times.
a). How many ways result in 6 tails and 2 heads?
b). How many ways result in 2 tails and 6 heads?
c). Compare your answers to part (a) and (b) and explain in a few sentences why the
comparison makes sense.
A local company has a 6 person management team and 20 employees. The company needs to select 3 people from the management team and 7 employees to attend a regional meeting. How many different possibilities are there for the group that can be sent to the regional meeting?
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