Explanation Given: Initial pressure, P 1 = 1 .22 atm Initial volume, V 1 = 13 .9 L Final volume, V 2 = 10 .3 L Explanation: According to Boyle’s law, under constant temperature and number of moles, we have P 1 V 1 = P 2 V 2 Substitute the given values in the above equation to get 1 .22 atm × 13 .9 L = P 2 × 10 .3 L ⇒ P 2 = 1

Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry

3rd Edition

ISBN: 9780321806383

Author: Nivaldo J. Tro

Publisher: PEARSON

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Question

Chapter 5, Problem 32E

Interpretation Introduction

To determine: The pressure exerted by the gas when volume of the gas sample is compressed.

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Chapter 5, Problem 31E

Chapter 5, Problem 33E

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Chapter 5 Solutions

Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry

Ch. 5 - Prob. 1SAQ Ch. 5 - Prob. 2SAQ Ch. 5 - Prob. 3SAQ Ch. 5 - Prob. 4SAQ Ch. 5 - Prob. 5SAQ Ch. 5 - Prob. 6SAQ Ch. 5 - Prob. 7SAQ Ch. 5 - Prob. 8SAQ Ch. 5 - Q9. A gas sample at STP contains 1.15 g oxygen and...Ch. 5 - Prob. 10SAQ

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