(a)
Interpretation:
Interpret formula of Copper(i) iodide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is CuI.
Explanation of Solution
Copper(i) is denoted as Cu+ while iodide denoted as I- and thus formula of given compound is CuI.
(b)
Interpretation:
Interpret formula of Cobaltous chloride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is CoCl2.
Explanation of Solution
Cobalt is present in lower oxidation state such as + 2 and thus formula of given compound is CoCl2.
(c)
Interpretation:
Interpret formula of Silver sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is AgF.
Explanation of Solution
Ag is present in lower oxidation state such as + 1 and thus formula of given compound is AgF.
(d)
Interpretation:
Interpret formula of Mercurous bromide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is HgBr2.
Explanation of Solution
Hg is present in lower oxidation state such as + 2 and thus formula of given compound is HgBr2.
(e)
Interpretation:
Interpret formula of Mercuric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Hg2 O3.
Explanation of Solution
Hg is present in higher oxidation state such as + 3 and thus formula of given compound is Hg2 O3.
(f)
Interpretation:
Interpret formula of Chromium (iii) sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Cr2 S3.
Explanation of Solution
Cr is present in higher oxidation state such as + 3 and thus formula of given compound is Cr2 S3.
(g)
Interpretation:
Interpret formula of Plumbic oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is PbO2.
Explanation of Solution
Pb is present in higher oxidation state such as + 4 and thus formula of given compound is PbO2.
(h)
Interpretation:
Interpret formula of Potassium nitride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is K3 N.
Explanation of Solution
N is present in oxidation state such as -3 and thus formula of given compound is K3 N.
(i)
Interpretation:
Interpret formula of Stannous fluoride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is SnF2.
Explanation of Solution
Sn2 + is present in lower oxidation state such as + 2 and thus formula of given compound is SnF2.
(j)
Interpretation:
Interpret formula of Ferric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Fe2 O3.
Explanation of Solution
Fe is present in higher oxidation state such as + 3 and thus formula of given compound is Fe2 O3.
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Chapter 5 Solutions
Introductory Chemistry: A Foundation
- Predict the product of this organic reaction: IZ + HO i P+H₂O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there is no reasonable possibility for P, check the No answer box under the drawing area. No Answer Click and drag to start drawing a structure. ☐ :arrow_forwardPredict the products of this organic reaction: 0 O ----- A + KOH ? CH3-CH2-C-O-CH2-C-CH3 Specifically, in the drawing area below draw the condensed structure of the product, or products, of this reaction. (If there's more than one product, draw them in any arrangement you like, so long as they aren't touching.) If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. No reaction Click anywhere to draw the first atom of your structure. X ⑤ èarrow_forwardPredict the products of this organic reaction: O CH3 + H2O + HCI A A? CH3-CH2-C-N-CH3 Specifically, in the drawing area below draw the condensed structure of the product, or products, of this reaction. If there's more than one product, draw them in any arrangement you like, so long as they aren't touching. If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. No Reaction Click anywhere to draw the first atom of your structure.arrow_forward
- What is the missing reactant in this organic reaction? R+ HO-C-CH2-CH3 0= CH3 CH3 —CH, C−NH—CH CH3 + H₂O Specifically, in the drawing area below draw the condensed structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. Note for advanced students: you may assume no products other than those shown above are formed. No Answer Click anywhere to draw the first atom of your structure. €arrow_forward个 CHEM&131 9267 - $25 - Intro to Mail - Hutchison, Allison (Student x Aktiv Learnin https://app.aktiv.com Draw the product of the reaction shown below. Ignore inorganic byproducts. + Na2Cr2O7 Acetone, H2SO4 Type here to search Dryng OH W Prarrow_forwardPredict the products of this organic reaction: OH + NaOH A? Specifically, in the drawing area below draw the skeletal ("line") structure of the product, or products, of this reaction. (If there's more than one product, draw them in any arrangement you like, so long as they aren't touching.) If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. No reaction Click and drag to start drawing a structure. ✓ Sarrow_forward
- Predict the products of this organic reaction: CH3-C-O-CH2-CH2-C-CH3 + H₂O ? A Specifically, in the drawing area below draw the condensed structure of the product, or products, of this reaction. (If there's more than one product, draw them in any arrangement you like, so long as they aren't touching.) If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. No reaction Click anywhere to draw the first atom of your structure. :☐ darrow_forwardDE d. Draw an arrow pushing mechanism for the following IN O CI N fo 人 P Polle DELL prt sc home end ins F5 F6 F7 F8 F9 F10 F11 F12arrow_forwardPredict the products of this organic reaction: + H₂O H* ? A Specifically, in the drawing area below draw the skeletal ("line") structure of the product, or products, of this reaction. (If there's more than one product, draw them in any arrangement you like, so long as they aren't touching.) If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. No Reaction Click and drag to start drawing a structure.arrow_forward
- Predict the major organic products of the reaction below and draw them on right side of the arrow. If there will be no significant reaction, check the box below the drawing area instead. C Cl CH, OH There will be no significant reaction. + pyridine G Click and drag to start drawing a structure.arrow_forwardWhat is the missing reactant in this organic reaction? H R+ H2O Δ OH 0= CH3-CH-O-CH3 + CH3-C-OH Specifically, in the drawing area below draw the condensed structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. No Answer Click anywhere to draw the first atom of your structure. dyarrow_forwardYou are trying to determine whether the following organic reaction can be done in a single synthesis step. If so, add any missing reagents or conditions in the drawing area below. If it isn't possible to do this reaction in a single synthesis step, check the box below the drawing area instead. Note for advanced students: if you have a choice of reagents to add, you should choose the least reactive and most economical reagents possible. Cl It isn't possible to do this reaction in a single synthesis step. + T OHarrow_forward
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