Chapter 5, Problem 20MCQ

To determine

Towrite:Inequality for the distance covered by the C.

Answer to Problem 20MCQ

  $d\le 18\frac{5}{12}\text{feet}$

Explanation of Solution

Given information:

Average distance covered by males $=17\text{feet}\text{5inches}=17\frac{5}{12}\text{feet}\mathrm{...}\left(1\text{inch}=\frac{1}{12}\text{feet}\right)$

C jumps at most 12 inches farther than Average distance covered by males.

Concept Used:

When two quantities are not equal, the comparison between them is often presented by certain symbols, this comparison is known as inequality and the symbols used for such comparison are known as inequality symbols.

There are four inequality symbols, $>$ , $<$ , $\ge$ , $\le$ namely “greater than”, “less than”, “greater than or equal to” and “less than or equal to” respectively.

Calculation:

Let’s suppose distance covered by C is $d$

Now basis the statement $d$ should be less than or equal to $17\frac{5}{12}\text{feet}$ plus 12 inches

This can be written using the inequality symbol as-

  $\begin{array}{l}d\le 17\frac{5}{12}+\frac{12}{12}\\ \Rightarrow d\le 17+\frac{5}{12}+\frac{12}{12}\\ \Rightarrow d\le \frac{\left(17\right)\left(12\right)+5+12}{12}\\ \Rightarrow d\le \frac{204+17}{12}\\ \Rightarrow d\le \frac{221}{12}\\ \Rightarrow d\le 18\frac{5}{12}\end{array}$