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Physics: Principles with Applications
7th Edition
ISBN: 9780321625922
Author: Douglas C. Giancoli
Publisher: Addison-Wesley
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Textbook Question
Chapter 5, Problem 1P
A child sitting 1.20 m from the center of a merry-go-round moves with a speed of 1.10 m/s. Calculate (a) the centripetal acceleration of the child and (b) the net horizontal force exerted on the child (mass = 22.5 kg)
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Students have asked these similar questions
Because the Earth rotates about its axis, a point on the equator experiences a centripetal acceleration of 0.033 7 m/s2, whereas a point at the poles experiences no centripetal acceleration. If a person at the equator has a mass of 75.0 kg, calculate (a) the gravitational force (true weight) on the person and (b) the normal force (apparent weight) on the person. (c) Which force is greater? Assume the Earth is a uniform sphere and take g = 9.800 m/s2.
A spacecraft flying horizontally over the surface of the moon at an elevation of 1500m with a speed of 350m/s, drops a package with a mass of 1200kg to astronauts on the surface. Use gm= 1.6m/s2 for the acceleration due to gravity on the Moon.
a)How long does it take the package to hit the surface after it is dropped?
b)How far ahead (distance) of the package’s landing spot should the package be released?
c)What is the velocity of the package just before it hits the surface?
d)What is the magnitude of the velocity of the package just before it hits the surface of the Moon?
When the Moon is directly overhead at sunset, the force by Earth on the Moon,
FEM,
is essentially at 90° to the force by the Sun on the Moon,
FSM,
as shown below. Given that
FEM = 1.98 ✕ 1020 N
and
FSM = 4.36 ✕ 1020 N,
all other forces on the Moon are negligible, and the mass of the Moon is 7.35 ✕ 1022 kg, determine the magnitude of the Moon's acceleration (in m/s2).
Chapter 5 Solutions
Physics: Principles with Applications
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