INTEGRAT PRINC OF ZOO(CONNECT ACCESS)
18th Edition
ISBN: 9781264177998
Author: HICKMAN
Publisher: MCG
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Chapter 5, Problem 19RQ
Summary Introduction
To explain: The role of mRNA, tRNA, and rRNA in polypeptide synthesis.
Introduction: The genetic information of DNA is based on the
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Trait: Neurofibromatosis
Forms of the trait:
The dominant form is neurofibromatosis, caused by the production of an abnormal form of the protein
neurofibromin. Affected individuals show spots of abnormal skin pigmentation and non-cancerous
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Nn
nn
nn
2
nn
Nn
A
3
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Chapter 5 Solutions
INTEGRAT PRINC OF ZOO(CONNECT ACCESS)
Ch. 5 - What is the relationship between homologous...Ch. 5 - Describe or diagram the sequence of events in...Ch. 5 - What are the designations of the sex chromosomes...Ch. 5 - Prob. 4RQCh. 5 - Diagram by Punnett square a cross between...Ch. 5 - Prob. 6RQCh. 5 - Assuming brown eyes (B) are dominant over blue...Ch. 5 - Prob. 8RQCh. 5 - Prob. 9RQCh. 5 - Prob. 10RQ
Ch. 5 - Assume that right-handedness (R) is genetically...Ch. 5 - Prob. 12RQCh. 5 - Prob. 13RQCh. 5 - Distinguish the following: euploidy, aneuploidy,...Ch. 5 - Prob. 15RQCh. 5 - Prob. 16RQCh. 5 - Prob. 17RQCh. 5 - Prob. 18RQCh. 5 - Prob. 19RQCh. 5 - Prob. 20RQCh. 5 - Prob. 21RQCh. 5 - Why do many mutations have no detectable effects...Ch. 5 - Distinguish between proto-oncogene and oncogene....Ch. 5 - Prob. 24RQCh. 5 - Outline the essential steps in the polymerase...Ch. 5 - Prob. 26RQCh. 5 - Prob. 27RQCh. 5 - Prob. 1FFT
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- foraging/diet type teeth tongue stomach intestines cecum Insectivory numerous, spiky, incisors procumbentExample: moleExample: shrew -- simple short mostly lacking Myrmecophagy absent or reduced in numbers, peg-likeExample: tamandua anteater extremely long simple, often roughened short small or lacking Terrestrial carnivory sharp incisors; long, conical canines; often carnassial cheek teeth; may have crushing molarsExample: dog -- simple short small Aquatic carnivory homodont, spiky, numerousExample: common dolphin -- simple or multichambered (cetaceans only) variable small or absent Sanguinivory very sharp upper incisors; reduced cheek teethExample: vampire bat grooved tubular, highly extensible long small or lacking Herbivory (except nectivores) incisors robust or absent; canines reduced or absent; diastema; cheek teeth enlarged with complex occlusal surfacesExample: beaver -- simple (hindgut fermenters) or multichambered (ruminants) long large Filter feeding none…arrow_forward3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 པར『ན་ cm 30 Species B 4/3, 1/1, 2/2, 4/4 cm 10 Species C 0/4, 0/0,3/3, 3/3 020arrow_forward3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 cm 30 Species B 0/4, 0/0, 3/3, 3/3 cm 10 Species C 4/3, 1/1, 2/2, 4/4 E 0 cm 20 AILarrow_forward
- Normal dive (for diving humans) normal breathing dive normal breathing Oz level CO₂ level urgent need to breathe Oz blackout zone high CO₂ triggers breathing 6. This diagram shows rates of oxygen depletion and carbon dioxide accumulation in the blood in relation to the levels needed to maintain consciousness and trigger the urgent need to breathe in diving humans. • How might the location and slope of the O2 line differ for diving marine mammals such as whales and dolphins? • How might the location and slope of the CO2 line differ for diving marine mammals such as whales and dolphins? • • Draw in predicted lines for O2 and CO2, based on your reasoning above. How might the location of the Urgent Need to Breathe line and the O2 Blackout Zone line differ for diving marine mammals? What physiological mechanisms account for each of these differences, resulting in the ability of marine mammals to stay submerged for long periods of time?arrow_forwardHow much ATP will be produced during the following metabolic scenario: Aerobic respiration of a 5mM lipid solution that is made up of one glycerol and an 8-carbon fatty acid and 12-carbon fatty acid. Recall that when glycerol breaks down to Glyceraldehyde-3-phosphate it costs one ATP but your get an extra FADH2. Every two carbons of a fatty acid break down to one acetyl-CoA. Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forwardIf a bacterium using aerobic respiration was to degrade one small protein molecule into 8 molecules of pyruvic acid, how many ATP would that cell make? Assume there is no other carbon source. Units cannot be entered in this style of question but the units of your answer should be in molecules of ATP.arrow_forward
- If a bacterium using aerobic respiration was to degrade a 30 mM solution of citric acid, how many ATP would that cell make? Assume no other carbon source is available. Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forwardHow much ATP will be produced during the following metabolic scenario: Aerobic respiration of a 5mM lipid solution that is made up of one glycerol and an 8-carbon fatty acid and 12-carbon fatty acid. Recall that when glycerol breaks down to Glyceraldehyde-3-phosphate it costs one ATP but your get an extra FADH2. Every two carbons of a fatty acid break down to one acetyl-CoA. (pathways will be provided on the exam) Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forwardWhen beta-lactamase was isolated from Staphylcoccus aureus and treated with a phosphorylating agent, only the active site, serine was phosphorylated. Additionally, the serine was found to constitute 0.35% (by weight) of this beta-lactamase enzyme. Using this, calculate the molecular weight of this enzyme and estimate the number of amino acids present in the polypeptide.arrow_forward
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