MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
5th Edition
ISBN: 9781305581159
Author: Nicholas J. Garber; Lester A. Hoel
Publisher: Cengage Learning US
Question
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Chapter 5, Problem 18P
To determine

(i)

The long- time average number of injury crashes per year at the site.

Expert Solution
Check Mark

Answer to Problem 18P

  ni=14.724Crashes/yr._

Explanation of Solution

Given:

Following information has been given to us: Length of road segment =7585 ft.

AADT =5250 veh/day.

Total number of injury crashes for 10 years =12.

Total number of fatal crashes for 10 years =3.

Total number of property crashes for 10 years = 48.

Assume k=2.51.

The applicable safety performance functions for injury, fatal, and property damage only

crashes are:

  SPinj=1.602×106 (length in feet)(AADT)0.491

  SPPDO=3.811×106 (length in feet)(AADT)0.491

Calculation:

We have the following formula for the number of fatal crashes:

  ni=numberoffatalcrashesSPinj

Where, SPinj=1.602×106 (length in feet)(AADT)0.491

  SPinj=1.602×106 (7585)(5250)0.491SPinj=0.815

Substituting the values, we have

  ni=120.815ni=14.724.

Conclusion:

Therefore, the long- time average number of injury crashes per year at the site is ni=14.724 Crashes/ yr.

To determine

(ii)

The long-time average number of fatal crashes per year at the site.

Expert Solution
Check Mark

Answer to Problem 18P

  nf=3.681Crashes/ year_.

Explanation of Solution

Given:

Following information has been given to us:

Length of road segment =7585 ft.

AADT =5250 veh/day.

Total number of injury crashes for 10 years =12.

Total number of fatal crashes for 10 years =3.

Total number of property crashes for 10 years = 48.

Assume k=2.51.

The applicable safety performance functions for injury, fatal, and property damage only

crashes are:

  SPinj=1.602×106 (length in feet)(AADT)0.491

  SPPDO=3.811×106 (length in feet)(AADT)0.491

Calculation:

We have the following formula for the number of fatal crashes:

  nf=numberoffatalcrashesSPinj

Where, SPinj=1.602×106 (length in feet)(AADT)0.491

  SPinj=1.602×106 (7585)(5250)0.491SPinj=0.815.

Substituting the values, we have

  nf=30.815nf=3.681

  nf=3.681Crashes/ year.

Conclusion:

Therefore, the number of fatal crashes per year at the site is 3.681Crashes/ year.

To determine

(iii)

The long-time average number of property damage only crashes per year at the site.

Expert Solution
Check Mark

Answer to Problem 18P

  nP=24.755Crashes/ year._

Explanation of Solution

Given:

Following information has been given to us:

Length of road segment =7585 ft.

AADT =5250 veh/day.

Total number of injury crashes for 10 years =12.

Total number of fatal crashes for 10 years =3.

Total number of property crashes for 10 years = 48.

Assume k=2.51.

The applicable safety performance functions for injury, fatal, and property damage only

crashes are:

  SPinj=1.602×106 (length in feet)(AADT)0.491

  SPPDO=3.811×106 (length in feet)(AADT)0.491

Calculation:

We have the following formula for the long-time average number of property damage only crashes per year at the site

  nP=numberofpropertydamage crashesSPPDO

Where, SPPDO=3.811×106 (length in feet)×(AADT)0.491

  SPPDO=3.811×106 (7585)×(5250)0.491SPPDO=1.939SPPDO=1.939Crashes/year.

Substituting the values, we have

  nP=481.939nP=24.755nP=24.755Crashes/ year.

Conclusion:

Therefore,the long-time average number of property damage only crashes per year at the site nP=24.755Crashes/ year.

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