|| BIO Force during a jump. An average person can reach a maximum height of about 60 em when jumping straight up from a crouched position. During the jump itself, the person's body from the knees up typically rises a distance of around 50 em. To keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump. (a) With what initial speed does the person leave the ground to reach a height of 60 em? (b) Make a free-body diagram of the person during the jump. (c) In terms of this jumper's weight W, what force does the ground exert on him or her during the jump?
|| BIO Force during a jump. An average person can reach a maximum height of about 60 em when jumping straight up from a crouched position. During the jump itself, the person's body from the knees up typically rises a distance of around 50 em. To keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump. (a) With what initial speed does the person leave the ground to reach a height of 60 em? (b) Make a free-body diagram of the person during the jump. (c) In terms of this jumper's weight W, what force does the ground exert on him or her during the jump?
|| BIO Force during a jump. An average person can reach a maximum height of about 60 em when jumping straight up from a crouched position. During the jump itself, the person's body from the knees up typically rises a distance of around 50 em. To keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump. (a) With what initial speed does the person leave the ground to reach a height of 60 em? (b) Make a free-body diagram of the person during the jump. (c) In terms of this jumper's weight W, what force does the ground exert on him or her during the jump?
Chapter 07, Problem 051
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A force F = (7.I0N)? + (4.00 N)ĵ + (5.00 N) k acts on a 1.70 kg mobile object that
moves from an initial position of di
: (3.70 m) î + (8.10 m)ĵ + (2.00 m) ê to a final
=
position of áf = (2.80 m)î + (8.50 m)} + (4.40 m) k in 1.70 s. Find (a) the work
done on the object by the force in the 1.70 s interval, (b) the average power due to the
force during that interval, and (c) the angle between vectors d; and df.
a dj.
(a) Number
Units
38.8
(b) NumberT22.8
Units
(c) NumberT12.43
UnitsTo (degrees)
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Chapter 07, Problem 084
Z Your answer is partially correct. Try again.
A force F = (2.51 + 8.4 + 6.4k) N :
acts on a 3.6kg object that moves in 2.3s from an initial position 1 = (3.4i + 3.6j + 3.2
3.28)
m to a final position
T2 = (5.3i + 4.0j + 8.2k ) m. Find (a) the work done on the object by the force in that time interval, (b) the average power due to the force during that time interval,
and (c) the angle between the vectors T1 and T2.
(a) Number
Units
(b) Number
Units
(c) Number
Units
(degrees)
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A body of mass m is on a horizontal plane with a coefficient of friction u, V; It moves at first speed. The object stops after traveling x distance. So which of the following is u equal to?
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