College Physics
OER 2016 Edition
ISBN: 9781947172173
Author: OpenStax
Publisher: OpenStax College
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Chapter 5, Problem 14PE
Calculate the maximum acceleration of a car that is heading up a 4° slope (one that makes an angle of 4° with the horizontal) under the following road conditions. Assume that only half the weight of the car is supported by the two drive wheels and that the coefficient of static friction is involved that—is, the tires are not allowed to slip during the acceleration. (Ignore rolling.) (a) On dry concrete. (b) On wet concrete. (c) On ice, assuming that
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(a) If half of the weight of a small 1.00×103kg utility truck is supported by its two drive wheels, what is the magnitude of the maximum acceleration it can achieve on dry concrete? (b) Will a metal cabinet lying on the wooden bed of the truck slip if it accelerates at this rate? (c) Solve both problems assuming the truck has four-wheel drive.
Calculate the maximum acceleration of a car that is heading up a 4º slope (one that makes an angle of 4º with the horizontal) under the following road conditions. Assume that only half the weight of the car is supported by the two drive wheels and that the coefficient of static friction is involved—that is, the tires are not allowed to slip during the acceleration. (Ignore rolling.)
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Chapter 5 Solutions
College Physics
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Show that the acceleration of any object down an incline where friction behaves simply (that is, where fk=kN ) is a=g(sinkcos). Note that the acceleration is independent of mass and reduces to the expression found in the previous problem when friction becomes negligibly small (k=0).arrow_forwardCalculate the maximum acceleration of a car that is heading down a 6.00° slope (one that makes an angle of 6.00° with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed on all four tires and that the coefficient of static friction is involved—that is, the tires are not allowed to slip during the deceleration. (Ignore rolling.) Calculate for a car: (a) On dry concrete. (b) On wet concrete. (c) On ice, assuming that μs = 0.100 , the same as for shoes on ice.arrow_forwardA car starts rolling down a 1-in-4 hill (1-in-4 means that for each 4 m traveled along the sloping road, the elevation change is 1 m). How fast is it going when it reaches the bottom after traveling 55 m? (a) Ignore friction. (b) Assume an effective coefficient of friction equal to 0.10.arrow_forward
- A 1,814 kg car is running on a vertical wall. The coefficient of static friction between the tires and the wall is 0.67, and the radius of the track is 7 m. Find the minimum speed of the car so it does not slip. Round the final answer to 1 decimal place.arrow_forwardA loading car is at rest on a track forming an angle of 25° with the vertical as shown. The gross weight of the car and its load is 5500 lb and this load is applied at a point 30 inches from the track, halfway between the two axels. The car is held in place by a cable attached 24 inches from the track. Determine the tension in the cable and the reaction at each pair of wheels.arrow_forwardThe FedEx and UPS boxes have almost reached the top of the inclined plane they have been moving along and are now arrangedThe UPS box has a mass of 3.0 kg, and the FedEx box has a mass of 1.0 kg. The inclined plane is frictionless;however, the horizontal floor has coefficients of static and kinetic friction of 0.5 and 0.2. The pulley is frictionless, and the massesof the pulley and cord are negligible. Answer the following about this system. a.What is the size of the normal force on the UPS box?b. This system will begin to move if released from rest. However, if youpressed with a downward force on the FedEx box, this system could remain at rest.What size force is required? Your solution should include two free-body diagrams.c. If the system was set into motion down the ramp, without the forcementioned in the previous part, what would be the acceleration of the system? Yoursolution should include two free-body diagrams.arrow_forward
- Gdarrow_forwardA car making a turn on a dry, banked highway ramp is experiencing friction. The angle of the bank is 40 degrees and the radius of turn is 78 m, what is the coefficient of static friction between the tires and the road if a 1350 kg car safely turn at 45m/s?arrow_forwardDetermine the force Prequired to force the 11° wedge under the 76-kg uniform crate which rests against the small stop at A. The coefficient of friction for all surfaces is 0.30. 2.3 m 1.2 m 76 kg A 1 11° Answer: P =arrow_forward
- How much horizontal force is needed to start pushing a 1850 kg truck if all 4 wheels are locked. us=0.6 uk =0.38arrow_forwardQuestion 19 In order to prevent muscle contraction from misaligning bones during healing (which can cause a permanent limp), injured or broken legs must be supported horizontally and at the same time kept under tension (traction) directed along the leg. One version of a device to accomplish this aim, the Russell traction apparatus, is shown in the figure below. This system allows the apparatus to support the full weight of the injured leg and at the same time provide the traction along the leg. If the leg to be supported weighs 47.0 N, what must be the weight of W? 25° 25° W Question 20 In order to prevent muscle contraction from misaligning bones during healing (which can cause a permanent limp), injured or broken legs must be supported horizontally and at the same time kept under tension (traction) directed along the leg. One version of a device to accomplish this aim, the Russell traction apparatus, is shown in the figure below. This system allows the apparatus to support the full…arrow_forwardThe coefficient of static friction µg between the 83-lb body and the 14° wedge is 0.37. Determine the magnitude of the force P required to begin raising the 83-lb body if (a) rollers of negligible friction are present under the wedge, as illustrated, and (b) the rollers are removed and the coefficient of static friction Hs = 0.37 applies at this surface as well. 83 lb 14° Answers: (a) P = i Ib (b) P = i Ibarrow_forward
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