DATABASE SYSTEMS (LOOSELEAF)-W/MINDTAP
13th Edition
ISBN: 9781337761833
Author: Coronel
Publisher: CENGAGE L
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Chapter 5, Problem 12RQ
Program Plan Intro
Primary key (PK):
- To identify each record in a table, at least there must be one data field, which should be unique.
- That is corresponding data field of every record should be unique.
- It is called primary key.
- Primary key is used to identify the unique record from a collection of records.
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Students have asked these similar questions
1. Create a Book record that implements the Comparable interface, comparing the
Book objects by year
- title: String
>
- author: String
- year: int
Book
+ compareTo(other Book: Book): int
+ toString(): String
Submit your source code on Canvas (Copy
your code to text box or upload.java file)
>
Comparable
2. Create a main method in Book record.
1) In the main method, create an array of 2 objects of Book with your choice of
title, author, and year.
2) Sort the array by year
3) Print the object. Override the toString in Book to match the example output:
@Javadoc Declaration Console X Properties
Book [Java Application] /Users/kuan/.p2/pool/plugins/org.eclipse.justj.openjdk.hotspo
[Book: year=1901, Book: year=2010]
Q5-The efficiency of a 200 KVA, single phase transformer is 98% when operating at full load 0.8
lagging p.f. the iron losses in the transformer is 2000 watt. Calculate the i) Full load copper losses ii)
half load copper losses and efficiency at half load. Ans: 1265.306 watt, 97.186%
2. Consider the following pseudocode for partition:
function partition (A,L,R)
pivotkey = A [R]
t = L
for i
L to R-1 inclusive:
if A[i] A[i]
t = t + 1
end if
end for
A [t] A[R]
return t
end function
Suppose we call partition (A,0,5) on A=[10,1,9,2,8,5]. Show the state of the list at the
indicated instances.
Initial A
After i=0 ends
After 1 ends
After i 2 ends
After i = 3 ends
After i = 4 ends
After final swap
10 19 285
[12 pts]
Chapter 5 Solutions
DATABASE SYSTEMS (LOOSELEAF)-W/MINDTAP
Ch. 5 - Prob. 1RQCh. 5 - What kinds of data would you store in an entity...Ch. 5 - Prob. 3RQCh. 5 - What is a subtype discriminator? Give an example...Ch. 5 - Prob. 5RQCh. 5 - What is a disjoint subtype? Give an example.Ch. 5 - What is the difference between partial...Ch. 5 - Prob. 8RQCh. 5 - According to the data model, is it required that...Ch. 5 - Prob. 10RQ
Ch. 5 - Prob. 11RQCh. 5 - Prob. 12RQCh. 5 - Prob. 13RQCh. 5 - Prob. 14RQCh. 5 - When implementing a 1:1 relationship, where should...Ch. 5 - What is time-variant data, and how would you deal...Ch. 5 - Prob. 17RQCh. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8CCh. 5 - Prob. 9CCh. 5 - Prob. 10C
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