Explanation Given: The diameter of the pipe ( d ) is 3 in. The volumetric flow ( Q ) is 90 ft 3 / min . The datum level at point B ( z B ) is 20 ft. The head loss ( h L ) is 1.5 ft . Calculation: The following assumptions are made in the problem: The water from A to B to considered as control volume. The Point A and B are opened to the atmosphere so the velocity at point A and B are zero. p A = p B = p atm = 0 . The stream is the large reservoir so the velocity at point A is zero. V A = 0 . The datum line A pass through point A so z A = 0 . Calculate the area of the pipe ( A B ) . A B = π d 2 4 A B = π ( 3 in . × 1 ft 12 in . ) 2 4 = 0.04908 ft 2 Calculate the velocity of water at B ( V B ) . Q = V B A B ( 90 ft 3 min × 1 min 60 s ) = V B × 0.04908 V B = 30.56 ft / s Refer Appendix A, “Physical Properties of Water versus Temperature (FPS Units)” The density of water ( ρ w ) at 32 ° F as 1.94 slug / ft 3 . Calculate the unit weight of water ( γ ) . γ = ρ w g γ = 1.94 × 32.2 = 62.468 lb / ft 3 Calculate the pump head ( h pump ) using the Energy equation

2nd Edition

ISBN: 9780134626055

Author: HIBBELER

Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)

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Applied Fluid Mechanics

A fluid is a substance that is continuously deformed by the application of shear stress. The rate of deformation of a fluid depends on its viscosity. The fluid tries to flow when it interacts with some other system.

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Chapter 5, Problem 107P

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