Explanation Given: Equation ( 16 ) from Theorem 8 : y 1 w ' + ( 2 y 1 ' + p y 1 ) w = 0 . Approach: Separate the y 1 , w terms and integrate. Calculation: Since, y 1 w ' + ( 2 y 1 ' + p y 1 ) w = 0 , rearranging terms gives y 1 w ' = − ( 2 y 1 ' + p y 1 ) w w ' w = − 2 y 1 ' y 1 − p d w w = − 2 d y 1 y 1 − p d t Integrate to get:

Pearson eText Fundamentals of Differential Equations with Boundary Value Problems -- Instant Access (Pearson+)

7th Edition

ISBN: 9780137394524

Author: R. Nagle, Edward Saff

Publisher: PEARSON+

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Chapter 4.7, Problem 48E

To determine

To find:

Solution to equation (16) from Theorem 8.

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Chapter 4.7, Problem 47E

Chapter 4.7, Problem 49E

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Pearson eText Fundamentals of Differential Equations with Boundary Value Problems -- Instant Access (Pearson+)

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