Concept explainers
What is the form of the limit
Want to see the full answer?
Check out a sample textbook solutionChapter 4 Solutions
MyLab Math with Pearson eText -- Standalone Access Card -- for Calculus: Early Transcendentals (3rd Edition)
Additional Math Textbook Solutions
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Precalculus
Elementary Statistics: Picturing the World (7th Edition)
Elementary Statistics
Calculus: Early Transcendentals (2nd Edition)
Basic Business Statistics, Student Value Edition
- Use the Squeeze Theorem to show that lim x² cos(207TX) = 0. X → 0 Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207tx), and h(x) = x². Then [0 ✓≤ cos(207TX) ≤ 1 f(x) V ≤ x² cos(207Tx) ≤ ? S . Since lim f(x) = lim_h(x) : = X → 0 X → 0 , by the Squeeze Theorem we have lim g(x) X → 0 =arrow_forwardState three part definition of continuityarrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage