Explanation Given : x 2 + 9 y + 10 x − 47 = 0 The given equation, x 2 + 9 y + 10 x − 47 = 0 First solve for y and then differentiate. x 2 + 9 y + 10 x − 47 = 0 y = − x 2 − 10 x + 47 9 Differentiate w .r .t x y ' = 1 9 ( − 2 x − 10 ) For maximum or minimum, y ' = 0 1 9 ( − 2 x − 10 ) = 0 x = − 5 Now double differentiate of y y ' ' = − 2 9 If y ' ' is negative at x = − 5 then maximum

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 4.6, Problem 5PS

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To find: The maximum value of x for which optimal value of y is obtained, x2+9y+10x−47=0

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Chapter 4.6, Problem 4PS

Chapter 4.6, Problem 6PS

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Chapter 4 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

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The maximum value of x for which optimal value of y is obtained, x 2 + 9 y + 10 x − 47 = 0

Solution Summary: The author explains that the given equation, x2+9y+10x-47=0, solves for y and then differentiates.

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To find: The maximum value of x for which optimal value of y is obtained, x2+9y+10x−47=0

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Chapter 4 Solutions