Explanation Given : f ( x ) = { 1 if x > 0 − 1 if x < 0 This is sign function, f ( x ) = | x | x If see the numerator is absolute function. It would be negative if x < 0 and positive if x > 0 . So, sign of f depends on x

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Question

Chapter 4.2, Problem 43PS

To determine

To check: The function is not constant but derivative becomes 0, f(x)={1if x>0−1if x<0

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Chapter 4.2, Problem 42PS

Chapter 4.2, Problem 44PS

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Chapter 4 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

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To check: The function is not constant but derivative becomes 0, f ( x ) = { 1 if x > 0 − 1 if x < 0

Solution Summary: The author explains the zero-derivative theorem. The function is not constant but derivative becomes 0.

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To check: The function is not constant but derivative becomes 0, f(x)={1if x>0−1if x<0

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Chapter 4 Solutions

To check: The function is not constant but derivative becomes 0, f ( x ) = { 1 if x &gt; 0 − 1 if x &lt; 0

Solution Summary: The author explains the zero-derivative theorem. The function is not constant but derivative becomes 0.

Concept explainers

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To check: The function is not constant but derivative becomes 0, f(x)={1if x>0−1if x<0

Want to see the full answer?

Chapter 4 Solutions

To check: The function is not constant but derivative becomes 0, f ( x ) = { 1 if x > 0 − 1 if x < 0