Explanation Given : 10 x 2 + 100 x − 20 y + 110 = 0 The given equation, 10 x 2 + 100 x − 20 y + 110 = 0 First solve for y and then differentiate. 10 x 2 + 100 x − 20 y + 100 = 0 y = − 10 x 2 − 100 x − 110 − 20 Differentiate w .r .t x y ' = − 1 20 ( − 20 x − 100 ) For maximum or minimum, y ' = 0 − 1 20 ( − 20 x − 100 ) = 0 x = − 5 Now double differentiate of y y ' ' = 1 If y ' ' is negative at x = − 5 then maximum

Student's Solution and Survival Manual for Calculus

7th Edition

ISBN: 9781524934040

Author: STRAUSS MONTY J, TODA MAGDALENA DANIELE, SMITH KARL J

Publisher: Kendall Hunt Publishing

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Chapter 4.6, Problem 4PS

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To find: The maximum value of x for which optimal value of y is obtained, 10x2+100x−20y+110=0

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Chapter 4.6, Problem 3PS

Chapter 4.6, Problem 5PS

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Chapter 4 Solutions

Student's Solution and Survival Manual for Calculus

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The maximum value of x for which optimal value of y is obtained, 10 x 2 + 100 x − 20 y + 110 = 0

Solution Summary: The author explains that the given equation, 10x2+100x-20y+110=0 first solves for y and then differentiates.

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To find: The maximum value of x for which optimal value of y is obtained, 10x2+100x−20y+110=0

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Chapter 4 Solutions