Explanation Let p ( t , 1 ( t + 1 ) 2 ) be a point on the graph of the curve y = 1 ( x + 1 ) 2 in the first quadrant the curve at p is L ( x ) = 1 ( t + 1 ) 2 − 2 ( x − t ) ( t + 1 ) 3 Which has x − intercept a = 3 t + 1 2 and y − intercept b = 3 t + 1 ( t + 1 ) 3 the area of the triangle in equation is A ( t ) = 1 2 a b = ( 3 t + 1 ) 2 4 ( t + 1 ) 3 A ' ( t ) =

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.

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Chapter 4.6, Problem 38E

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Find the maximum area of a triangle formed by the axes and a tangent line to the graph of the graph of y=(x+1)−2 with x>0

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Chapter 4.6, Problem 37E

Chapter 4.6, Problem 39E

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Chapter 4 Solutions

CALCULUS W/SAPLING ACCESS >IC<

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Find the maximum area of a triangle formed by the axes and a tangent line to the graph of the graph of y = ( x + 1 ) − 2 with x > 0

Solution Summary: The author explains how to determine the maximum area of a triangle formed by the axes and tangent line to the graph of y=(x+1)2.

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Find the maximum area of a triangle formed by the axes and a tangent line to the graph of the graph of y=(x+1)−2 with x>0

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Chapter 4 Solutions

Find the maximum area of a triangle formed by the axes and a tangent line to the graph of the graph of y = ( x + 1 ) − 2 with x &gt; 0

Solution Summary: The author explains how to determine the maximum area of a triangle formed by the axes and tangent line to the graph of y=(x+1)2.

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Find the maximum area of a triangle formed by the axes and a tangent line to the graph of the graph of y=(x+1)−2 with x>0

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Chapter 4 Solutions

Find the maximum area of a triangle formed by the axes and a tangent line to the graph of the graph of y = ( x + 1 ) − 2 with x > 0