Explanation Given information: A function is given as, f ( x ) = x 3 + 4 x 2 − x − 4 . Concept used: If f ' ' ( c ) = 0 or f ' ' ( c ) does not exists, and f ' ' ( x ) changes sign at x = c , then f has an inflection point at x = c . Calculation: Given function is, f ( x ) = x 3 + 4 x 2 − x − 4 . Plotting the graph of above function. From below graph inflection point seems to be at x = − 1.33 Given function is, f ( x ) = x 3 + 4 x 2 − x − 4 . Taking first derivative, f ' ( x ) = 3 x 2 + 8 x − 1 Taking second derivative, f ' ' ( x ) = 6 x + 8 At point of inflection, f &

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.4, Problem 3E

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The point of inflection of given function.

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Chapter 4.4, Problem 2E

Chapter 4.4, Problem 4E

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Chapter 4 Solutions

CALCULUS W/SAPLING ACCESS >IC<

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The point of inflection of given function.

Solution Summary: The author explains the point of inflection of a given function, f(x)=x3+4x2x4.

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Chapter 4 Solutions