Chapter 4.6, Problem 2PSA

To determine

To find: The slope of given line.

Answer to Problem 2PSA

  $-\frac{3}{5}$ .

Explanation of Solution

Given information:

Line $\overleftrightarrow{AB}$ has a slope of $1\frac{2}{3}$ and $\overleftrightarrow{AB}\perp \overleftrightarrow{CD}$ .

Concept used: Slope of two perpendicular lines are negative reciprocal of each other.

  $m_1=-\frac{1}{m_2}$ .

Calculation:

Given line $\overleftrightarrow{AB}$ has a slope of $1\frac{2}{3}$ and $\overleftrightarrow{AB}\perp \overleftrightarrow{CD}$ .

Therefore slope of line $\overleftrightarrow{CD}$ would be negative reciprocal of line $\overleftrightarrow{AB}$ .

  $\text{So, slope of line }\overleftrightarrow{CD}=-\frac{1}{1\frac{2}{3}}=-\frac{3}{5}$ .

Hence, slope of line $\overleftrightarrow{CD}$ is $-\frac{3}{5}$ .