Chapter 4.6, Problem 1PSA

a)

To determine

To calculate: Slope of line

Answer to Problem 1PSA

  $\frac{8}{9}$

Explanation of Solution

Given information: Coordinates of two points.

Formula used: Slope of line joining $(x_1,y_1)$ and $(x_2,y_2)$ is $\frac{y_2-y_1}{x_2-x_1}$

Calculation: $\text{Slop}=\frac{15-7}{10-1}=\frac{8}{9}$

b)

To determine

To calculate: Slope of line

Answer to Problem 1PSA

  $\frac{1}{7}$

Explanation of Solution

Given information: Coordinates of two points.

Formula used: Slope of line joining $(x_1,y_1)$ and $(x_2,y_2)$ is $\frac{y_2-y_1}{x_2-x_1}$

Calculation: $\text{Slop}=\frac{7-6}{5+2}=\frac{1}{7}$

c)

To determine

To calculate: Slope of line

Answer to Problem 1PSA

  $\frac{11}{6}$

Explanation of Solution

Given information: Coordinates of two points.

Formula used: Slope of line joining $(x_1,y_1)$ and $(x_2,y_2)$ is $\frac{y_2-y_1}{x_2-x_1}$

Calculation: $\text{Slop}=\frac{4+7}{-2+8}=\frac{11}{6}$

d)

To determine

To calculate: Slope of line

Answer to Problem 1PSA

0

Explanation of Solution

Given information: Coordinates of two points.

Formula used: Slope of line joining $(x_1,y_1)$ and $(x_2,y_2)$ is $\frac{y_2-y_1}{x_2-x_1}$

Calculation: $\text{Slop}=\frac{4-4}{5+2}=0$

e)

To determine

To calculate: Slope of line

Answer to Problem 1PSA

not defined

Explanation of Solution

Given information: Coordinates of two points.

Formula used: Slope of line joining $(x_1,y_1)$ and $(x_2,y_2)$ is $\frac{y_2-y_1}{x_2-x_1}$

Calculation: $\text{Slop}=\frac{7-9}{\sqrt{3}-\sqrt{3}}=\text{not}\text{defined}$

f)

To determine

To calculate: Slope of line

Answer to Problem 1PSA

  $\frac{5C}{a}$

Explanation of Solution

Given information: Coordinates of two points.

Formula used: Slope of line joining $(x_1,y_1)$ and $(x_2,y_2)$ is $\frac{y_2-y_1}{x_2-x_1}$

Calculation: $\text{Slop}=\frac{6c+9c}{5a-2a}=\frac{5c}{a}$