For Exercises 1-16, identify which functions shown here ( f , g , h , and so on) have the given characteristics f x = sin π 2 x + 3 g x = − 3 cos 1 2 x − π 4 h x = 3 sin − 1 2 x − π 5 k x = − 3 sec 2 x + π m x = 2 csc 2 x − π 2 − 3 n x = 3 tan x − π 2 p x = − 2 cot 1 2 x + π t x = − 3 + 2 cos x Has a range of all real numbers
For Exercises 1-16, identify which functions shown here ( f , g , h , and so on) have the given characteristics f x = sin π 2 x + 3 g x = − 3 cos 1 2 x − π 4 h x = 3 sin − 1 2 x − π 5 k x = − 3 sec 2 x + π m x = 2 csc 2 x − π 2 − 3 n x = 3 tan x − π 2 p x = − 2 cot 1 2 x + π t x = − 3 + 2 cos x Has a range of all real numbers
Solution Summary: The author explains that the following functions have a range of all real numbers: f(x)=mathrmsin
For Exercises 1-16, identify which functions shown here (
f
,
g
,
h
,
and so on) have the given characteristics
f
x
=
sin
π
2
x
+
3
g
x
=
−
3
cos
1
2
x
−
π
4
h
x
=
3
sin
−
1
2
x
−
π
5
k
x
=
−
3
sec
2
x
+
π
m
x
=
2
csc
2
x
−
π
2
−
3
n
x
=
3
tan
x
−
π
2
p
x
=
−
2
cot
1
2
x
+
π
t
x
=
−
3
+
2
cos
x
A factorization A = PDP 1 is not unique. For A=
7 2
-4 1
1
1
5 0
2
1
one factorization is P =
D=
and P-1
30
=
Use this information with D₁
=
to find a matrix P₁ such that
-
-1 -2
0 3
1
-
- 1
05
A-P,D,P
P1
(Type an integer or simplified fraction for each matrix element.)
Matrix A is factored in the form PDP 1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace.
30 -1
-
1 0 -1
400
0
0 1
A=
3 4 3
0 1 3
040
3 1 3
0 0
4
1
0
0
003
-1 0 -1
Select the correct choice below and fill in the answer boxes to complete your choice.
(Use a comma to separate vectors as needed.)
A basis for the corresponding eigenspace is {
A. There is one distinct eigenvalue, λ =
B. In ascending order, the two distinct eigenvalues are λ₁
...
=
and 2
=
Bases for the corresponding eigenspaces are {
and ( ), respectively.
C. In ascending order, the three distinct eigenvalues are λ₁ =
=
12/2
=
and 3 = Bases for the corresponding eigenspaces are
{}, }, and {
respectively.
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