Physics for Scientists and Engineers With Modern Physics
9th Edition
ISBN: 9781133953982
Author: SERWAY, Raymond A./
Publisher: Cengage Learning
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Chapter 45, Problem 7OQ
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The reason for the spiral shape.
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An alpha particle (m = 6.68 x 1027 kg, q = +2 e.c.) is fired through a velocity selector that is created by an electric field of 4.5 x 105 N/C and a magnetic field of 0.90 T. It then enters a second magnetic field of 1.5 T.
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Chapter 45 Solutions
Physics for Scientists and Engineers With Modern Physics
Ch. 45.1 - When a nucleus undergoes fission, the two daughter...Ch. 45.2 - Prob. 45.2QQCh. 45.3 - Prob. 45.3QQCh. 45.4 - Prob. 45.4QQCh. 45 - Prob. 1OQCh. 45 - Prob. 2OQCh. 45 - Prob. 3OQCh. 45 - Prob. 4OQCh. 45 - Prob. 5OQCh. 45 - Prob. 6OQ
Ch. 45 - Prob. 7OQCh. 45 - Prob. 8OQCh. 45 - Prob. 9OQCh. 45 - Prob. 1CQCh. 45 - Prob. 2CQCh. 45 - Prob. 3CQCh. 45 - Prob. 4CQCh. 45 - Prob. 5CQCh. 45 - Prob. 6CQCh. 45 - Prob. 7CQCh. 45 - Prob. 8CQCh. 45 - Prob. 1PCh. 45 - Prob. 2PCh. 45 - Prob. 3PCh. 45 - Prob. 4PCh. 45 - Prob. 5PCh. 45 - Prob. 6PCh. 45 - Prob. 7PCh. 45 - Prob. 8PCh. 45 - Prob. 9PCh. 45 - Prob. 10PCh. 45 - Prob. 11PCh. 45 - Prob. 12PCh. 45 - Prob. 13PCh. 45 - Prob. 14PCh. 45 - Prob. 15PCh. 45 - Prob. 16PCh. 45 - Prob. 18PCh. 45 - Prob. 19PCh. 45 - Prob. 20PCh. 45 - Prob. 21PCh. 45 - Prob. 22PCh. 45 - Prob. 23PCh. 45 - Prob. 24PCh. 45 - Prob. 25PCh. 45 - Prob. 26PCh. 45 - Prob. 27PCh. 45 - Prob. 28PCh. 45 - Prob. 29PCh. 45 - Prob. 30PCh. 45 - Prob. 31PCh. 45 - Prob. 32PCh. 45 - Prob. 33PCh. 45 - Prob. 34PCh. 45 - Prob. 35PCh. 45 - Prob. 36PCh. 45 - Prob. 37PCh. 45 - Prob. 41PCh. 45 - Prob. 42PCh. 45 - Prob. 43PCh. 45 - Prob. 44PCh. 45 - Prob. 45PCh. 45 - Prob. 46APCh. 45 - Prob. 47APCh. 45 - Prob. 48APCh. 45 - Prob. 49APCh. 45 - Prob. 51APCh. 45 - Prob. 52APCh. 45 - Prob. 53APCh. 45 - Prob. 54APCh. 45 - Prob. 55APCh. 45 - Prob. 56APCh. 45 - Prob. 57APCh. 45 - Prob. 58APCh. 45 - Prob. 59APCh. 45 - Prob. 60APCh. 45 - Prob. 61APCh. 45 - Prob. 62APCh. 45 - Prob. 63APCh. 45 - Prob. 64APCh. 45 - Prob. 65APCh. 45 - Prob. 66APCh. 45 - Prob. 67APCh. 45 - Prob. 68APCh. 45 - Prob. 69APCh. 45 - Prob. 70APCh. 45 - Prob. 71APCh. 45 - Prob. 72APCh. 45 - Prob. 73AP
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- A mystery particle enters the region between the plates of a Thomson apparatus as shown in Figure 4.6. The deflection angle θ is measured to be 0.20 radians (downwards) for this particle when V = 2000 V, ℓ = 10.0 cm, and d = 2.00 cm. If a perpendicular magnetic field of magnitude 4.57 × 10−2 T is applied simultaneously with the electric field, the particle passes through the plates without deflection. (a) Find q/m for this particle. (b) Identify the particle. (c) Find the horizontal speed with which the particle entered the plates. (d) Must we use relativistic mechanics for this particle?arrow_forwardA common way to focus a beam of charged particles is to use an electric field and a magnetic field together. Based on the relative strength and orientation of the two fields, you can tune the Coulomb and Lorentz forces to direct the beam of particles. This technique is common in mass spectrometers and scanning electron microscopes. You want to focus a beam of positively charged particles moving in the -z direction. The particles have a mass of 1.50e-22 kg and you orient a 0.316 T magnetic field in the -x direction. What direction do the particles feel the Lorentz force from the magnetic field? The particle is moving with a velocity of 4.63e+05m and has a charge of 2.36e-16 C. What is the magnitude of the Lorentz force on the particle in Newton? FLorentz N = E = If you want the Lorentz force and the Coulomb force to exactly cancel each other, what magnitude of electric field should you apply in S C What direction should you orient the electric field so that the Coulomb force and the…arrow_forwardIn a particular decay process, two charged particles, labeled "A" and "B" were released, which enter into a region of magnetic field with different speeds as shown. The magnetic field is uniform pointing into the page. One of the particles curves to the left, while the other curved to the right. What is the nature of the charged on the particle? Hint : Use the right hand rule X X X X X X X X X X X X X V A VBX X X X X X X X A B O A = positively charged ; B = negatively charged Both are positively charged since the direction of curving ONLY depends on the speed Both are negatively charged since the direction of curving ONLY depends on the speed B = positively charged ; A = negatively charged X.arrow_forward
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