Physicians often treat thyroid cancer with a radioactive form of iodine called iodine – 131 ( I 131 ) . The radiological half-life of I 131 is approximately 8 days, but the biological half-life for most individuals is 4.2 days. The biological half-life is shorter because in addition to I 131 being lost to decay, the iodine is also excreted from the body in urine, sweat, and saliva. For a patient treated with 100 mCi (millicuries) of I 131 , the radioactivity level R (in mCi) after t days is given by R =100 ( 2 ) − t / 4.2 . a. State law mandates that the patient stay in an isolated hospital room for 2 days after treatment with I 131 . Determine the radioactivity level at the end of 2 days. Round to the nearest whole unit. b. After the patient is released from the hospital, the patient is directed to avoid direct human contact until the radioactivity level drops below 30 mCi. For how many days after leaving the hospital will the patient need to stay in isolation? Round to the nearest tenth of a day.
Physicians often treat thyroid cancer with a radioactive form of iodine called iodine – 131 ( I 131 ) . The radiological half-life of I 131 is approximately 8 days, but the biological half-life for most individuals is 4.2 days. The biological half-life is shorter because in addition to I 131 being lost to decay, the iodine is also excreted from the body in urine, sweat, and saliva. For a patient treated with 100 mCi (millicuries) of I 131 , the radioactivity level R (in mCi) after t days is given by R =100 ( 2 ) − t / 4.2 . a. State law mandates that the patient stay in an isolated hospital room for 2 days after treatment with I 131 . Determine the radioactivity level at the end of 2 days. Round to the nearest whole unit. b. After the patient is released from the hospital, the patient is directed to avoid direct human contact until the radioactivity level drops below 30 mCi. For how many days after leaving the hospital will the patient need to stay in isolation? Round to the nearest tenth of a day.
Solution Summary: The author calculates the radioactivity level at the end of 2 days when the physicians treat thyroid cancer with radioactive form of iodine-131.
Physicians often treat thyroid cancer with a radioactive form of iodine called iodine –
131
(
I
131
)
. The radiological half-life of
I
131
is approximately 8 days, but the biological half-life for most individuals is 4.2 days. The biological half-life is shorter because in addition to
I
131
being lost to decay, the iodine is also excreted from the body in urine, sweat, and saliva.
For a patient treated with 100 mCi (millicuries) of
I
131
, the radioactivity level R (in mCi) after t days is given by
R
=100
(
2
)
−
t
/
4.2
.
a. State law mandates that the patient stay in an isolated hospital room for 2 days after treatment with
I
131
. Determine the radioactivity level at the end of 2 days. Round to the nearest whole unit.
b. After the patient is released from the hospital, the patient is directed to avoid direct human contact until the radioactivity level drops below 30 mCi. For how many days after leaving the hospital will the patient need to stay in isolation? Round to the nearest tenth of a day.
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Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
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