Identify whether the SD is around 1, 2, or 10 for the given list.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 4.5, Problem 4ED

a.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

a.

Expert Solution

Answer to Problem 4ED

The SD is around 1.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50)}=(−1,1,−1,1,−1,1,−1,1,−1,1)

Here, all deviations from the average is ±1.

Therefore, the SD is around 1.

b.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

b.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50)}=(−2,2,−2,2,−2,2,−2,2,−2,2)

Here, all deviations from the average is ±2.

Therefore, the SD is around 2.

c.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

c.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

Condition:

If the spread of the numbers around the average is larger, then the value of SD is larger.
If the spread of the numbers around the average is smaller, then the value of SD is smaller.

The difference between the given observations and the average is,

Deviations={(48−50),(51−50),(49−50),(52−50),(47−50),(52−50),(46−50),(51−50),(53−50),(51−50)}=(−2,1,−1,2,−3,2,−4,1,3,1)

Here, the given data set has less spread. Hence, the SD is around 2.

d.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

d.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(54−50),(49−50),(46−50),(49−50),(51−50),(53−50),(50−50),(50−50),(49−50),(49−50)}=(4,−1,−4,−1,1,3,0,0,−1,−1)

Here, the given data set has less spread. Hence, the SD is around 2.

e.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

e.

Expert Solution

Answer to Problem 4ED

The SD is around 10.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(60−50),(36−50),(31−50),(50−50),(48−50),(50−50),(54−50),(56−50),(62−50),(53−50)}=(10,−14,−19,0,−2,0,4,6,12,3)

Here, the spread of the numbers around the average is larger. This provide the largest SD.

Therefore, the SD is around 10.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 2

Question

Chapter 4.5, Problem 4ED

a.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

a.

Expert Solution

Answer to Problem 4ED

The SD is around 1.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50)}=(−1,1,−1,1,−1,1,−1,1,−1,1)

Here, all deviations from the average is ±1.

Therefore, the SD is around 1.

b.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

b.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50)}=(−2,2,−2,2,−2,2,−2,2,−2,2)

Here, all deviations from the average is ±2.

Therefore, the SD is around 2.

c.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

c.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

Condition:

If the spread of the numbers around the average is larger, then the value of SD is larger.
If the spread of the numbers around the average is smaller, then the value of SD is smaller.

The difference between the given observations and the average is,

Deviations={(48−50),(51−50),(49−50),(52−50),(47−50),(52−50),(46−50),(51−50),(53−50),(51−50)}=(−2,1,−1,2,−3,2,−4,1,3,1)

Here, the given data set has less spread. Hence, the SD is around 2.

d.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

d.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(54−50),(49−50),(46−50),(49−50),(51−50),(53−50),(50−50),(50−50),(49−50),(49−50)}=(4,−1,−4,−1,1,3,0,0,−1,−1)

Here, the given data set has less spread. Hence, the SD is around 2.

e.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

e.

Expert Solution

Answer to Problem 4ED

The SD is around 10.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(60−50),(36−50),(31−50),(50−50),(48−50),(50−50),(54−50),(56−50),(62−50),(53−50)}=(10,−14,−19,0,−2,0,4,6,12,3)

Here, the spread of the numbers around the average is larger. This provide the largest SD.

Therefore, the SD is around 10.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 4.5, Problem 4ED

a.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

a.

Expert Solution

Answer to Problem 4ED

The SD is around 1.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50)}=(−1,1,−1,1,−1,1,−1,1,−1,1)

Here, all deviations from the average is ±1.

Therefore, the SD is around 1.

b.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

b.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50)}=(−2,2,−2,2,−2,2,−2,2,−2,2)

Here, all deviations from the average is ±2.

Therefore, the SD is around 2.

c.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

c.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

Condition:

If the spread of the numbers around the average is larger, then the value of SD is larger.
If the spread of the numbers around the average is smaller, then the value of SD is smaller.

The difference between the given observations and the average is,

Deviations={(48−50),(51−50),(49−50),(52−50),(47−50),(52−50),(46−50),(51−50),(53−50),(51−50)}=(−2,1,−1,2,−3,2,−4,1,3,1)

Here, the given data set has less spread. Hence, the SD is around 2.

d.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

d.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(54−50),(49−50),(46−50),(49−50),(51−50),(53−50),(50−50),(50−50),(49−50),(49−50)}=(4,−1,−4,−1,1,3,0,0,−1,−1)

Here, the given data set has less spread. Hence, the SD is around 2.

e.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

e.

Expert Solution

Answer to Problem 4ED

The SD is around 10.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(60−50),(36−50),(31−50),(50−50),(48−50),(50−50),(54−50),(56−50),(62−50),(53−50)}=(10,−14,−19,0,−2,0,4,6,12,3)

Here, the spread of the numbers around the average is larger. This provide the largest SD.

Therefore, the SD is around 10.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 4.5, Problem 4ED

a.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

a.

Expert Solution

Answer to Problem 4ED

The SD is around 1.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50)}=(−1,1,−1,1,−1,1,−1,1,−1,1)

Here, all deviations from the average is ±1.

Therefore, the SD is around 1.

b.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

b.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50)}=(−2,2,−2,2,−2,2,−2,2,−2,2)

Here, all deviations from the average is ±2.

Therefore, the SD is around 2.

c.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

c.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

Condition:

If the spread of the numbers around the average is larger, then the value of SD is larger.
If the spread of the numbers around the average is smaller, then the value of SD is smaller.

The difference between the given observations and the average is,

Deviations={(48−50),(51−50),(49−50),(52−50),(47−50),(52−50),(46−50),(51−50),(53−50),(51−50)}=(−2,1,−1,2,−3,2,−4,1,3,1)

Here, the given data set has less spread. Hence, the SD is around 2.

d.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

d.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(54−50),(49−50),(46−50),(49−50),(51−50),(53−50),(50−50),(50−50),(49−50),(49−50)}=(4,−1,−4,−1,1,3,0,0,−1,−1)

Here, the given data set has less spread. Hence, the SD is around 2.

e.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

e.

Expert Solution

Answer to Problem 4ED

The SD is around 10.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(60−50),(36−50),(31−50),(50−50),(48−50),(50−50),(54−50),(56−50),(62−50),(53−50)}=(10,−14,−19,0,−2,0,4,6,12,3)

Here, the spread of the numbers around the average is larger. This provide the largest SD.

Therefore, the SD is around 10.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 4.5, Problem 4ED

a.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

a.

Expert Solution

Answer to Problem 4ED

The SD is around 1.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50)}=(−1,1,−1,1,−1,1,−1,1,−1,1)

Here, all deviations from the average is ±1.

Therefore, the SD is around 1.

b.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

b.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50)}=(−2,2,−2,2,−2,2,−2,2,−2,2)

Here, all deviations from the average is ±2.

Therefore, the SD is around 2.

c.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

c.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

Condition:

If the spread of the numbers around the average is larger, then the value of SD is larger.
If the spread of the numbers around the average is smaller, then the value of SD is smaller.

The difference between the given observations and the average is,

Deviations={(48−50),(51−50),(49−50),(52−50),(47−50),(52−50),(46−50),(51−50),(53−50),(51−50)}=(−2,1,−1,2,−3,2,−4,1,3,1)

Here, the given data set has less spread. Hence, the SD is around 2.

d.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

d.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(54−50),(49−50),(46−50),(49−50),(51−50),(53−50),(50−50),(50−50),(49−50),(49−50)}=(4,−1,−4,−1,1,3,0,0,−1,−1)

Here, the given data set has less spread. Hence, the SD is around 2.

e.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

e.

Expert Solution

Answer to Problem 4ED

The SD is around 10.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(60−50),(36−50),(31−50),(50−50),(48−50),(50−50),(54−50),(56−50),(62−50),(53−50)}=(10,−14,−19,0,−2,0,4,6,12,3)

Here, the spread of the numbers around the average is larger. This provide the largest SD.

Therefore, the SD is around 10.

Answer 6

Chapter 4.5, Problem 4ED

a.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

a.

Expert Solution

Answer to Problem 4ED

The SD is around 1.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50)}=(−1,1,−1,1,−1,1,−1,1,−1,1)

Here, all deviations from the average is ±1.

Therefore, the SD is around 1.

Answer 7

Chapter 4.5, Problem 4ED

a.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer 8

a.

Expert Solution

Answer to Problem 4ED

The SD is around 1.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50),(49−50),(51−50)}=(−1,1,−1,1,−1,1,−1,1,−1,1)

Here, all deviations from the average is ±1.

Therefore, the SD is around 1.

Answer 13

b.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

b.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50)}=(−2,2,−2,2,−2,2,−2,2,−2,2)

Here, all deviations from the average is ±2.

Therefore, the SD is around 2.

Answer 14

b.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer 15

b.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50),(48−50),(52−50)}=(−2,2,−2,2,−2,2,−2,2,−2,2)

Here, all deviations from the average is ±2.

Therefore, the SD is around 2.

Answer 20

c.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

c.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

Condition:

If the spread of the numbers around the average is larger, then the value of SD is larger.
If the spread of the numbers around the average is smaller, then the value of SD is smaller.

The difference between the given observations and the average is,

Deviations={(48−50),(51−50),(49−50),(52−50),(47−50),(52−50),(46−50),(51−50),(53−50),(51−50)}=(−2,1,−1,2,−3,2,−4,1,3,1)

Here, the given data set has less spread. Hence, the SD is around 2.

Answer 21

c.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer 22

c.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Answer 23

c.

Expert Solution

Answer 24

c.

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Calculation:

The average of the given list is 50.

Condition:

If the spread of the numbers around the average is larger, then the value of SD is larger.
If the spread of the numbers around the average is smaller, then the value of SD is smaller.

The difference between the given observations and the average is,

Deviations={(48−50),(51−50),(49−50),(52−50),(47−50),(52−50),(46−50),(51−50),(53−50),(51−50)}=(−2,1,−1,2,−3,2,−4,1,3,1)

Here, the given data set has less spread. Hence, the SD is around 2.

Answer 27

d.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

d.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(54−50),(49−50),(46−50),(49−50),(51−50),(53−50),(50−50),(50−50),(49−50),(49−50)}=(4,−1,−4,−1,1,3,0,0,−1,−1)

Here, the given data set has less spread. Hence, the SD is around 2.

Answer 28

d.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer 29

d.

Expert Solution

Answer to Problem 4ED

The SD is around 2.

Answer 30

d.

Expert Solution

Answer 31

d.

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(54−50),(49−50),(46−50),(49−50),(51−50),(53−50),(50−50),(50−50),(49−50),(49−50)}=(4,−1,−4,−1,1,3,0,0,−1,−1)

Here, the given data set has less spread. Hence, the SD is around 2.

Answer 34

e.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

e.

Expert Solution

Answer to Problem 4ED

The SD is around 10.

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(60−50),(36−50),(31−50),(50−50),(48−50),(50−50),(54−50),(56−50),(62−50),(53−50)}=(10,−14,−19,0,−2,0,4,6,12,3)

Here, the spread of the numbers around the average is larger. This provide the largest SD.

Therefore, the SD is around 10.

Answer 35

e.

To determine

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer 36

e.

Expert Solution

Answer to Problem 4ED

The SD is around 10.

Answer 37

e.

Expert Solution

Answer 38

e.

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Calculation:

The average of the given list is 50.

The difference between the given observations and the average is,

Deviations={(60−50),(36−50),(31−50),(50−50),(48−50),(50−50),(54−50),(56−50),(62−50),(53−50)}=(10,−14,−19,0,−2,0,4,6,12,3)

Here, the spread of the numbers around the average is larger. This provide the largest SD.

Therefore, the SD is around 10.

Answer 41

Ch. 4.2 - Prob. 1EA Ch. 4.2 - Prob. 2EA Ch. 4.2 - Prob. 3EA Ch. 4.2 - Prob. 4EA Ch. 4.2 - Prob. 5EA Ch. 4.2 - Prob. 6EA Ch. 4.2 - Prob. 7EA Ch. 4.2 - Prob. 8EA Ch. 4.2 - Prob. 9EA Ch. 4.3 - Prob. 1EB

Identify whether the SD is around 1, 2, or 10 for the given list.

Concept explainers

Videos

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer to Problem 4ED

Explanation of Solution

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer to Problem 4ED

Explanation of Solution

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer to Problem 4ED

Explanation of Solution

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer to Problem 4ED

Explanation of Solution

Identify whether the SD is around 1, 2, or 10 for the given list.

Answer to Problem 4ED

Explanation of Solution

Want to see more full solutions like this?

Chapter 4 Solutions