The prior probabilities of events A1, A2 and A3 if P(A1)=0.20, P(A2)=0.50 and P(A3)=0.30. The conditional probabilities of event B given events A1, A2 and A3 are P(B | A1)=0.50, P(B | A2)=0.40 and P(P | A3)=0.30. a) Calculate P (BQ A1), P(BQ A2) and P(BQ A3). b) Use Bayes' theorem to calculate the posterior probability P(A2 | B). c) Use the tree method to employ Bayes' theorem to calculate P(A1 | B), P(A2 | B), and P(A3 | B)

Q: Suppose among a population of students 50% own a laptop and 30% of the total have a laptop but no…

A: Answer:- Given information is, P( laptop) = 50% = 0.50 P( laptop and no tablet) = 30% = 0.30  P(…

Q: Suppose A and B are events with P(A) = 0.3, P(B) = 0.85, and P(B|A) = 0.6. Find the value of P(A or…

A: given data  P(A) = 0.3 P(B) = 0.85 P(B|A) = 0.6 P(A or B) = ?

Q: A and B are events such that P(A) = 0.4 and P(B| A) = 0.7. Find P(A&B).

A: The formula for dependent event P (A and B) is given below:

Q: The two events A and B are such that P(A)=0.6, P(B)=0.2, p(A|B)= 0.1. Calculate the probabilities…

A:

Q: Given P(A and B) = 0.42, P(A) = 0.92, and P(B) = 0.05 are events A and B independent or dependent?

A:

Q: The P(A)=0.48P(A)=0.48 and the P(B)=0.06P(B)=0.06. Events AA and BB are mutually exclusive. What is…

A: Given, P(A)=0.48 P(B)=0.06 P(A or B)=?

Q: Suppose that E and F are two events and that P(E) = 0.5 and P(F|E) = 0.2. What is P(E and F)? P(E…

A: GivenP(E)=0.5P(F|E)=0.2

Q: If A and B are independent events with P(A) = 0.30 and P(A and B) = 0.15, then Find P(B).

A: Here For 2 independent events A and B  P(A)= 0.3 P(A and B) =0.15

Q: Suppose that A and B are events such that P(A) = 2/7 and P(A&B) = 3/25. Determine P(B| A).

A:

Q: If B CA and A and B are two events such that P (A) = 3 P (B) and A UB = S find P (B) ?

A: Answer: For the given data,

Q: 4. P4 = P(A | Bº). (P1, P2, P3, P4) =(

A: From the given information we have P(B) = 47/210 P(Bc) = 1 - P(B) = 1 - 47/210 = 163/210

Q: For two events A and B , P(A)=0.7 , P(B)=0.4 , and P(A∩B)=0.28. Determine whether or not A and B are…

A: Given that  P(A)=0.7 , P(B)=0.4 , and P(A∩B)=0.28

Q: Let A and B be two events such that P(A) = 1/6 While P(A or B) = 1/2. Let P(B) = P. For what values…

A: P(A or B)= P(A)+P(B)-P(A and B) For A and B to be independent P(A and B)=P(A).P(B) Therefore, P(A or…

Q: Suppose that A, B are two independent events, with P(A) = .1 and P(B) = .2. Find P(A|B).

A:

Q: illed. Assume also that the pr. the child of a professional laborer becomes a professional, skilled,…

A: *answer:

Q: 1 Let A and B be independent events with P(A) = P(An B) = P(A U B) = and P(B) = 13. Find P(An B) and…

A:

Q: For events A, B, and C, we have the following probabilities: P(A) 0.7, P(B) = 0.5, P(C) = 0.3, P(A…

A:

Q: If A and B are independent events with P(A) = 0.25 and P(B) = 0.60,then P(A|B) is?

A: Given: A and B are independent events. P(A)=0.25P(B)=0.6 The objective is to find P(AB).

Q: A car can travel from Town A to Town C by using the four roads below. The probabilities of these…

A: the probability that a car cannot reach Town C from Town A = P(H1) * P(H2) * P(H3) * P(H4)

Q: information, (a)Are the events L and F mutually exclusive? (b)Are the events L and F independent?

A: It is given asP(L) = 0.58P(F) = 0.5P(L∩F) = 0.31

Q: Let A and B be two events with probabilities P(A) = 0.6, P(B) = 0.4 and P(A and B) = 0.2. (a) Find…

A: Given: P(A) = 0.6 P(B) = 0.4 P(A and B) = 0.2 Plug in all the values in the formula.

Q: If A and B are independent events P(A) = 0.2 P(A or B) =0.63 Find P(B)

A: Consider, If A and B are independent events, P(A)=0.26 and P(A or B)=0.63

Q: Suppose that C and D are two events such that P(C)=1/2 and P(C & D)=3/10. What is P(D|C)​?

A:

Q: Suppose that E and F are two events and that P(E)=0.8 and P(F|E)=0.5. What is P(E and F)​?

A: Given data,  P(E)=0.8  P(F|E)=0.5 P(E and F)​=?

Q: Suppose that E and F are two events and that P(E and F)=0.48, P(F)=0.55, and P(E)=0.5. What is P(F…

A: Suppose that E and F are two events and that P(E and F)= 0.48 P(F)=0.55 and P(E)=0.5 What is P(F |E)…