The number of neutrons after reaction.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 45, Problem 1OQ

To determine

The number of neutrons after reaction.

Expert Solution & Answer

Answer to Problem 1OQ

Option (c) 3.

Explanation of Solution

In this reaction, before and after the reaction the mass number must be conserved.

The total mass number before the reaction is the sum of the mass number of U235 plus the mass number of neutron, which is equal to 235+1=236.

The total mass number after the reaction is the sum of the mass numbers of I137 and Y96, and is equal to 137+96=233. This implies the mass number is not conserved and is lag by 3. Thus, there must be three neutrons should emit to maintain the conservation.

Conclusion:

Therefore, the number of neutron produced is 3.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

You are standing a distance x = 1.75 m away from this mirror. The object you are looking at is y = 0.29 m from the mirror. The angle of incidence is θ = 30°. What is the exact distance from you to the image?

For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you

A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).

Answer 2

Question

Chapter 45, Problem 1OQ

To determine

The number of neutrons after reaction.

Expert Solution & Answer

Answer to Problem 1OQ

Option (c) 3.

Explanation of Solution

In this reaction, before and after the reaction the mass number must be conserved.

The total mass number before the reaction is the sum of the mass number of U235 plus the mass number of neutron, which is equal to 235+1=236.

The total mass number after the reaction is the sum of the mass numbers of I137 and Y96, and is equal to 137+96=233. This implies the mass number is not conserved and is lag by 3. Thus, there must be three neutrons should emit to maintain the conservation.

Conclusion:

Therefore, the number of neutron produced is 3.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 45, Problem 1OQ

To determine

The number of neutrons after reaction.

Expert Solution & Answer

Answer to Problem 1OQ

Option (c) 3.

Explanation of Solution

In this reaction, before and after the reaction the mass number must be conserved.

The total mass number before the reaction is the sum of the mass number of U235 plus the mass number of neutron, which is equal to 235+1=236.

The total mass number after the reaction is the sum of the mass numbers of I137 and Y96, and is equal to 137+96=233. This implies the mass number is not conserved and is lag by 3. Thus, there must be three neutrons should emit to maintain the conservation.

Conclusion:

Therefore, the number of neutron produced is 3.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 45, Problem 1OQ

To determine

The number of neutrons after reaction.

Expert Solution & Answer

Answer to Problem 1OQ

Option (c) 3.

Explanation of Solution

In this reaction, before and after the reaction the mass number must be conserved.

The total mass number before the reaction is the sum of the mass number of U235 plus the mass number of neutron, which is equal to 235+1=236.

The total mass number after the reaction is the sum of the mass numbers of I137 and Y96, and is equal to 137+96=233. This implies the mass number is not conserved and is lag by 3. Thus, there must be three neutrons should emit to maintain the conservation.

Conclusion:

Therefore, the number of neutron produced is 3.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 45, Problem 1OQ

To determine

The number of neutrons after reaction.

Expert Solution & Answer

Answer to Problem 1OQ

Option (c) 3.

Explanation of Solution

In this reaction, before and after the reaction the mass number must be conserved.

The total mass number before the reaction is the sum of the mass number of U235 plus the mass number of neutron, which is equal to 235+1=236.

The total mass number after the reaction is the sum of the mass numbers of I137 and Y96, and is equal to 137+96=233. This implies the mass number is not conserved and is lag by 3. Thus, there must be three neutrons should emit to maintain the conservation.

Conclusion:

Therefore, the number of neutron produced is 3.

Answer 6

Chapter 45, Problem 1OQ

To determine

The number of neutrons after reaction.

Expert Solution & Answer

Answer to Problem 1OQ

Option (c) 3.

Explanation of Solution

In this reaction, before and after the reaction the mass number must be conserved.

The total mass number before the reaction is the sum of the mass number of U235 plus the mass number of neutron, which is equal to 235+1=236.

The total mass number after the reaction is the sum of the mass numbers of I137 and Y96, and is equal to 137+96=233. This implies the mass number is not conserved and is lag by 3. Thus, there must be three neutrons should emit to maintain the conservation.

Conclusion:

Therefore, the number of neutron produced is 3.

Answer 7

Chapter 45, Problem 1OQ

To determine

The number of neutrons after reaction.

Answer 8

Expert Solution & Answer

Answer to Problem 1OQ

Option (c) 3.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

In this reaction, before and after the reaction the mass number must be conserved.

The total mass number before the reaction is the sum of the mass number of U235 plus the mass number of neutron, which is equal to 235+1=236.

The total mass number after the reaction is the sum of the mass numbers of I137 and Y96, and is equal to 137+96=233. This implies the mass number is not conserved and is lag by 3. Thus, there must be three neutrons should emit to maintain the conservation.