MyLab Statistics with Pearson eText -- Standalone Access Card -- for Biostatistics for the Biological and Health Sciences (My Stat Lab)
2nd Edition
ISBN: 9780134748870
Author: Marc M. Triola, Mario F. Triola, Jason Roy
Publisher: PEARSON
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Chapter 4.5, Problem 18SLCT
a)
To determine
To find the crude mortality rate for Florida and the crude mortality rate for the United States.
a)
Expert Solution
Answer to Problem 18SLCT
The crude mortality rate for Florida = 0.0091
The crude mortality rate for the United States = 0.0080
Explanation of Solution
Given:
| Age | ||||
| 0-24 | 25-64 | 65 and older | Total | |
| Florida deaths | 3625 | 39820 | 129395 | 172840 |
| Florida population | 5716861 | 9842031 | 3375303 | 18934195 |
| U.S. deaths | 63208 | 619982 | 1832268 | 2515458 |
| U.S. population | 103542603 | 163960163 | 45296729 | 312799495 |
| Total | 109326297 | 174461996 | 50633695 | 334421988 |
Formula:
The crude mortality rate for Florida is,
The crude mortality rate for U.S. is,
We can not compare this crude mortality rate as there are different number of deaths for each age group. So, this might be misleading the results if we compare total crude mortality rate of Florida with U.S.
b)
To determine
To find the mortality rate of Florida and United States for age group 65 and older.
b)
Expert Solution
Answer to Problem 18SLCT
The mortality rate for Florida = 0.0383
The mortality rate for the United States = 0.0405
Explanation of Solution
Given:
| Age | ||||
| 0-24 | 25-64 | 65 and older | Total | |
| Florida deaths | 3625 | 39820 | 129395 | 172840 |
| Florida population | 5716861 | 9842031 | 3375303 | 18934195 |
| U.S. deaths | 63208 | 619982 | 1832268 | 2515458 |
| U.S. population | 103542603 | 163960163 | 45296729 | 312799495 |
| Total | 109326297 | 174461996 | 50633695 | 334421988 |
Formula:
The mortality rate for Florida is,
The mortality rate for U.S. is,
The mortality rate of U.S. is higher than mortality rate of Florida.
c)
To determine
To find the percentage of population of Florida and U.S. is made up of people aged 65 and older.
c)
Expert Solution
Answer to Problem 18SLCT
The percentage of population of Florida is made up of people aged 65 and older = 17.8%
The percentage of population of United States is made up of people aged 65 and older = 14.5%
Explanation of Solution
Given:
| Age | ||||
| 0-24 | 25-64 | 65 and older | Total | |
| Florida deaths | 3625 | 39820 | 129395 | 172840 |
| Florida population | 5716861 | 9842031 | 3375303 | 18934195 |
| U.S. deaths | 63208 | 619982 | 1832268 | 2515458 |
| U.S. population | 103542603 | 163960163 | 45296729 | 312799495 |
| Total | 109326297 | 174461996 | 50633695 | 334421988 |
Formula:
The percentage of population of Florida is made up of people aged 65 and older
The percentage of population of U.S. is made up of people aged 65 and older
There is highest percentage of Florida people for age group 65 and older as compare to U.S. population.
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Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined.
1.What percent of the refunds are more than $3,500?
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A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts?
1. Compute the probability of a value between 44.0 and 55.0.
(The question requires finding probability value between 44 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 44, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the answer of the second part.)
2. Compute the probability of a value greater than 55.0.
Use the same formula, x=55 and subtract the answer from 1.
3. Compute the probability of a value between 52.0 and 55.0.
(The question requires finding probability value between 52 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 52, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the…
Chapter 4 Solutions
MyLab Statistics with Pearson eText -- Standalone Access Card -- for Biostatistics for the Biological and Health Sciences (My Stat Lab)
Ch. 4.1 - Prob. 1SLCTCh. 4.1 - Prob. 2SLCTCh. 4.1 - Prob. 3SLCTCh. 4.1 - Prob. 4SLCTCh. 4.1 - Prob. 5SLCTCh. 4.1 - Prob. 6SLCTCh. 4.1 - Prob. 7SLCTCh. 4.1 - Prob. 8SLCTCh. 4.1 - Prob. 9SLCTCh. 4.1 - Prob. 10SLCT
Ch. 4.1 - Prob. 11SLCTCh. 4.1 - Prob. 12SLCTCh. 4.1 - Prob. 13SLCTCh. 4.1 - Prob. 14SLCTCh. 4.1 - Prob. 15SLCTCh. 4.1 - Prob. 16SLCTCh. 4.1 - Prob. 17SLCTCh. 4.1 - Prob. 18SLCTCh. 4.1 - Prob. 19SLCTCh. 4.1 - Prob. 20SLCTCh. 4.1 - Prob. 21SLCTCh. 4.1 - Prob. 22SLCTCh. 4.1 - Prob. 23SLCTCh. 4.1 - Prob. 24SLCTCh. 4.1 - Prob. 25SLCTCh. 4.1 - Prob. 26SLCTCh. 4.1 - Prob. 27SLCTCh. 4.1 - Prob. 28SLCTCh. 4.1 - Prob. 29SLCTCh. 4.1 - Prob. 30SLCTCh. 4.1 - Prob. 31SLCTCh. 4.1 - Prob. 32SLCTCh. 4.1 - Prob. 33SLCTCh. 4.1 - Prob. 34SLCTCh. 4.1 - Prob. 35SLCTCh. 4.1 - Prob. 36SLCTCh. 4.1 - Prob. 37SLCTCh. 4.1 - Prob. 38SLCTCh. 4.1 - Prob. 39SLCTCh. 4.1 - Prob. 40SLCTCh. 4.2 - Prob. 1SLCTCh. 4.2 - Prob. 2SLCTCh. 4.2 - Prob. 3SLCTCh. 4.2 - Prob. 4SLCTCh. 4.2 - Prob. 5SLCTCh. 4.2 - Prob. 6SLCTCh. 4.2 - Prob. 7SLCTCh. 4.2 - Prob. 8SLCTCh. 4.2 - Prob. 9SLCTCh. 4.2 - Prob. 10SLCTCh. 4.2 - Prob. 11SLCTCh. 4.2 - Prob. 12SLCTCh. 4.2 - Prob. 13SLCTCh. 4.2 - Prob. 14SLCTCh. 4.2 - Prob. 15SLCTCh. 4.2 - Prob. 16SLCTCh. 4.2 - Prob. 17SLCTCh. 4.2 - Prob. 18SLCTCh. 4.2 - Prob. 19SLCTCh. 4.2 - Prob. 20SLCTCh. 4.2 - Prob. 21SLCTCh. 4.2 - Prob. 22SLCTCh. 4.2 - Prob. 23SLCTCh. 4.2 - Prob. 24SLCTCh. 4.2 - Prob. 25SLCTCh. 4.2 - Prob. 26SLCTCh. 4.2 - Prob. 27SLCTCh. 4.2 - Prob. 28SLCTCh. 4.2 - Prob. 29SLCTCh. 4.2 - Prob. 30SLCTCh. 4.2 - Prob. 31SLCTCh. 4.2 - Prob. 32SLCTCh. 4.2 - Prob. 33SLCTCh. 4.2 - Prob. 34SLCTCh. 4.3 - Prob. 1SLCTCh. 4.3 - Prob. 2SLCTCh. 4.3 - Prob. 3SLCTCh. 4.3 - Prob. 4SLCTCh. 4.3 - Prob. 5SLCTCh. 4.3 - Prob. 6SLCTCh. 4.3 - Prob. 7SLCTCh. 4.3 - Prob. 8SLCTCh. 4.3 - Prob. 9SLCTCh. 4.3 - Prob. 10SLCTCh. 4.3 - Prob. 11SLCTCh. 4.3 - Prob. 12SLCTCh. 4.3 - Prob. 13SLCTCh. 4.3 - Prob. 14SLCTCh. 4.3 - Prob. 15SLCTCh. 4.3 - Prob. 16SLCTCh. 4.3 - Prob. 17SLCTCh. 4.3 - Prob. 18SLCTCh. 4.3 - Prob. 19SLCTCh. 4.3 - Prob. 20SLCTCh. 4.3 - Prob. 21SLCTCh. 4.3 - Prob. 22SLCTCh. 4.3 - Prob. 23SLCTCh. 4.3 - Prob. 24SLCTCh. 4.3 - Prob. 25SLCTCh. 4.4 - Prob. 1SLCTCh. 4.4 - Prob. 2SLCTCh. 4.4 - Prob. 3SLCTCh. 4.4 - Prob. 4SLCTCh. 4.4 - Prob. 5SLCTCh. 4.4 - Prob. 6SLCTCh. 4.4 - Prob. 7SLCTCh. 4.4 - Prob. 8SLCTCh. 4.4 - Prob. 9SLCTCh. 4.4 - Prob. 10SLCTCh. 4.4 - Prob. 11SLCTCh. 4.4 - Prob. 12SLCTCh. 4.4 - Prob. 13SLCTCh. 4.4 - Prob. 14SLCTCh. 4.4 - Prob. 15SLCTCh. 4.4 - Prob. 16SLCTCh. 4.4 - Prob. 17SLCTCh. 4.4 - Prob. 18SLCTCh. 4.5 - Prob. 1SLCTCh. 4.5 - Prob. 2SLCTCh. 4.5 - Prob. 3SLCTCh. 4.5 - Prob. 4SLCTCh. 4.5 - Prob. 5SLCTCh. 4.5 - Prob. 6SLCTCh. 4.5 - Prob. 7SLCTCh. 4.5 - Prob. 8SLCTCh. 4.5 - Prob. 9SLCTCh. 4.5 - Prob. 10SLCTCh. 4.5 - Prob. 11SLCTCh. 4.5 - Prob. 12SLCTCh. 4.5 - Prob. 13SLCTCh. 4.5 - Prob. 14SLCTCh. 4.5 - Prob. 15SLCTCh. 4.5 - Prob. 16SLCTCh. 4.5 - Prob. 17SLCTCh. 4.5 - Prob. 18SLCTCh. 4.5 - Prob. 19SLCTCh. 4.5 - Prob. 20SLCTCh. 4.5 - Prob. 21SLCTCh. 4.6 - Prob. 1SLCTCh. 4.6 - Prob. 2SLCTCh. 4.6 - Prob. 3SLCTCh. 4.6 - Prob. 4SLCTCh. 4.6 - Prob. 5SLCTCh. 4.6 - Prob. 6SLCTCh. 4.6 - Prob. 7SLCTCh. 4.6 - Prob. 8SLCTCh. 4.6 - Prob. 9SLCTCh. 4.6 - Prob. 10SLCTCh. 4.6 - Prob. 11SLCTCh. 4.6 - Prob. 12SLCTCh. 4.6 - Prob. 13SLCTCh. 4.6 - Prob. 14SLCTCh. 4.6 - Prob. 15SLCTCh. 4.6 - Prob. 16SLCTCh. 4.6 - Prob. 17SLCTCh. 4.6 - Prob. 18SLCTCh. 4.6 - Prob. 19SLCTCh. 4.6 - Prob. 20SLCTCh. 4.6 - Prob. 21SLCTCh. 4.6 - Prob. 22SLCTCh. 4.6 - Prob. 23SLCTCh. 4.6 - Prob. 24SLCTCh. 4.6 - Prob. 25SLCTCh. 4.6 - Prob. 26SLCTCh. 4.6 - Prob. 27SLCTCh. 4.6 - Prob. 28SLCTCh. 4.6 - Prob. 29SLCTCh. 4.6 - Prob. 30SLCTCh. 4.6 - Prob. 31SLCTCh. 4.6 - Prob. 32SLCTCh. 4 - Prob. 1CQQCh. 4 - Prob. 2CQQCh. 4 - Prob. 3CQQCh. 4 - Prob. 4CQQCh. 4 - Prob. 5CQQCh. 4 - Prob. 6CQQCh. 4 - Prob. 7CQQCh. 4 - Prob. 8CQQCh. 4 - Prob. 9CQQCh. 4 - Prob. 10CQQCh. 4 - Prob. 1RECh. 4 - Prob. 2RECh. 4 - Prob. 3RECh. 4 - Prob. 4RECh. 4 - Prob. 5RECh. 4 - Prob. 6RECh. 4 - Prob. 7RECh. 4 - Prob. 8RECh. 4 - Prob. 9RECh. 4 - Prob. 10RECh. 4 - Prob. 11RECh. 4 - Prob. 12RECh. 4 - Prob. 13RECh. 4 - Prob. 14RECh. 4 - Prob. 1CRECh. 4 - Prob. 2CRECh. 4 - Prob. 3CRECh. 4 - Prob. 4CRECh. 4 - Prob. 5CRE
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