Beginning Statistics, 2nd Edition
Beginning Statistics, 2nd Edition
2nd Edition
ISBN: 9781932628678
Author: Carolyn Warren; Kimberly Denley; Emily Atchley
Publisher: Hawkes Learning Systems
Question
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Chapter 4.5, Problem 13E

(a)

To determine

To find:

The number of different schedules possible if he needs to have an equal number of symphonies from Mozart, Haydn, and Schubert.

(a)

Expert Solution
Check Mark

Answer to Problem 13E

The number of different schedules possible if he needs to have an equal number of symphonies from Mozart, Haydn, and Schubert is 1.2490697e+23.

Explanation of Solution

Given:

In choosing music to play at a charity fund-raising event, Marlow has 41 Mozart, 104 Haydn, and 8 Schubert Symphonies from which to choose. He is setting up a schedule of the 12 songs to be played during the show.

Formula Used:

Formula to calculate the number of combinations,

Cnr=n!r!(nr)!

Where, n is the number of distinct objects, and r is the number of objects selected from a group of n distinct objects.

Calculation:

12 songs can be played in the show from 41 Mozart, 104 Haydn and 8 Schubert symphonies. If an equal number of songs are to be chosen from Mozart, Haydn And Schubert, Marlow must choose 4 symphonies of Mozart, Haydn And Schubert.

4 Mozart symphonies out of 41 can be chosen:

C414=41!4!(414)!=41!4!37!=41×405×3913×38×37!(4×3×2×1)×37!=101270

4 Haydn symphonies out of 104 can be chosen:

C1044=104!4!(1044)!=104!4!100!=10413×103×10234×101×100!(4×3×2×1)×100!=4598126

4 Schubert symphonies out of 8 can be chosen:

C84=8!4!(84)!=8!4!4!=8×7×62×5×4!(4×3×2×1)×4!=560

Total number of arrangements:

P1212=12!(1212)!=12!0!=12!=479001600

The number of different schedules possible if he needs to have an equal number of symphonies from Mozart, Haydn, and Schubert is:

C414×C1044×C84×P1212=101270×4598126×560×479001600=1.2490697e+23

Thus, the number of different schedules possible if he needs to have an equal number of symphonies from Mozart, Haydn, and Schubert is 1.2490697e+23.

(b)

To determine

To find:

The probability that all 12 symphonies are by Mozart, if the songs are chosen randomly.

(b)

Expert Solution
Check Mark

Answer to Problem 13E

The probability that all 12 symphonies are by Mozart, if the songs are chosen randomly is 3.579429631972963e6.

Explanation of Solution

Calculation:

There are 41 Mozart, 104 Haydn and 8 Schubert symphonies, and 12 songs are to be chosen randomly in C15312 ways:

C15312=153!12!(15312)!=153!12!141!=153×152×151×150×149×148×147×146×145×144×143×142×141!(12×11×10×9×8×7×6×5×4×3×2×1)×141!=220667975965944780,

if all 12 symphonies are by Mozart, it can be chosen in C4112.

C4112=41!12!(4112)!=4112!29!=41×40×39×38×37×36×35×34×33×32×31×30×29!(12×11×10×9×8×7×6×5×4×3×2×1)×29!=7898654920

The required probability is:

C4112C15312=7898654920220667975965944780=3.579429631972963e6

Thus, the probability that all 12 symphonies are by Mozart, if the songs are chosen randomly is 3.579429631972963e6.

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Chapter 4 Solutions

Beginning Statistics, 2nd Edition

Ch. 4.1 - Prob. 11ECh. 4.1 - Prob. 12ECh. 4.1 - Prob. 13ECh. 4.1 - Prob. 14ECh. 4.1 - Prob. 15ECh. 4.1 - Prob. 16ECh. 4.1 - Prob. 17ECh. 4.1 - Prob. 18ECh. 4.1 - Prob. 19ECh. 4.1 - Prob. 20ECh. 4.1 - Prob. 21ECh. 4.1 - Prob. 22ECh. 4.1 - Prob. 23ECh. 4.1 - Prob. 24ECh. 4.1 - Prob. 25ECh. 4.1 - Prob. 26ECh. 4.2 - Prob. 1ECh. 4.2 - Prob. 2ECh. 4.2 - Prob. 3ECh. 4.2 - Prob. 4ECh. 4.2 - Prob. 5ECh. 4.2 - Prob. 6ECh. 4.2 - Prob. 7ECh. 4.2 - Prob. 8ECh. 4.2 - Prob. 9ECh. 4.2 - Prob. 10ECh. 4.2 - Prob. 11ECh. 4.2 - Prob. 12ECh. 4.2 - Prob. 13ECh. 4.2 - Prob. 14ECh. 4.2 - Prob. 15ECh. 4.2 - Prob. 16ECh. 4.2 - Prob. 17ECh. 4.2 - Prob. 18ECh. 4.2 - Prob. 19ECh. 4.2 - Prob. 20ECh. 4.2 - Prob. 21ECh. 4.2 - Prob. 22ECh. 4.2 - Prob. 23ECh. 4.2 - Prob. 24ECh. 4.2 - Prob. 25ECh. 4.2 - Prob. 26ECh. 4.2 - Prob. 27ECh. 4.2 - Prob. 28ECh. 4.2 - Prob. 29ECh. 4.2 - Prob. 30ECh. 4.2 - Prob. 31ECh. 4.3 - Prob. 1ECh. 4.3 - Prob. 2ECh. 4.3 - Prob. 3ECh. 4.3 - Prob. 4ECh. 4.3 - Prob. 5ECh. 4.3 - Prob. 6ECh. 4.3 - Prob. 7ECh. 4.3 - Prob. 8ECh. 4.3 - Prob. 9ECh. 4.3 - Prob. 10ECh. 4.3 - Prob. 11ECh. 4.3 - Prob. 12ECh. 4.3 - Prob. 13ECh. 4.3 - Prob. 14ECh. 4.3 - Prob. 15ECh. 4.3 - Prob. 16ECh. 4.3 - Prob. 17ECh. 4.3 - Prob. 18ECh. 4.3 - Prob. 19ECh. 4.3 - Prob. 20ECh. 4.3 - Prob. 21ECh. 4.3 - Prob. 22ECh. 4.3 - Prob. 23ECh. 4.3 - Prob. 24ECh. 4.3 - Prob. 25ECh. 4.3 - Prob. 26ECh. 4.3 - Prob. 27ECh. 4.3 - Prob. 28ECh. 4.3 - Prob. 29ECh. 4.3 - Prob. 30ECh. 4.3 - Prob. 31ECh. 4.4 - Prob. 1ECh. 4.4 - Prob. 2ECh. 4.4 - Prob. 3ECh. 4.4 - Prob. 4ECh. 4.4 - Prob. 5ECh. 4.4 - Prob. 6ECh. 4.4 - Prob. 7ECh. 4.4 - Prob. 8ECh. 4.4 - Prob. 9ECh. 4.4 - Prob. 10ECh. 4.4 - Prob. 11ECh. 4.4 - Prob. 12ECh. 4.4 - Prob. 13ECh. 4.4 - Prob. 14ECh. 4.4 - Prob. 15ECh. 4.4 - Prob. 16ECh. 4.4 - Prob. 17ECh. 4.4 - Prob. 18ECh. 4.4 - Prob. 19ECh. 4.4 - Prob. 20ECh. 4.4 - Prob. 21ECh. 4.4 - Prob. 22ECh. 4.4 - Prob. 23ECh. 4.4 - Prob. 24ECh. 4.4 - Prob. 25ECh. 4.4 - Prob. 26ECh. 4.4 - Prob. 27ECh. 4.4 - Prob. 28ECh. 4.4 - Prob. 29ECh. 4.4 - Prob. 30ECh. 4.4 - Prob. 31ECh. 4.4 - Prob. 32ECh. 4.4 - Prob. 33ECh. 4.4 - Prob. 34ECh. 4.4 - Prob. 35ECh. 4.4 - Prob. 36ECh. 4.4 - Prob. 37ECh. 4.4 - Prob. 38ECh. 4.4 - Prob. 39ECh. 4.4 - Prob. 40ECh. 4.4 - Prob. 41ECh. 4.4 - Prob. 42ECh. 4.4 - Prob. 43ECh. 4.4 - Prob. 44ECh. 4.4 - Prob. 45ECh. 4.4 - Prob. 46ECh. 4.4 - Prob. 47ECh. 4.4 - Prob. 48ECh. 4.4 - Prob. 49ECh. 4.4 - Prob. 50ECh. 4.4 - Prob. 51ECh. 4.4 - Prob. 52ECh. 4.5 - Prob. 1ECh. 4.5 - Prob. 2ECh. 4.5 - Prob. 3ECh. 4.5 - Prob. 4ECh. 4.5 - Prob. 5ECh. 4.5 - Prob. 6ECh. 4.5 - Prob. 7ECh. 4.5 - Prob. 8ECh. 4.5 - Prob. 9ECh. 4.5 - Prob. 10ECh. 4.5 - Prob. 11ECh. 4.5 - Prob. 12ECh. 4.5 - Prob. 13ECh. 4.5 - Prob. 14ECh. 4.CR - Prob. 1CRCh. 4.CR - Prob. 2CRCh. 4.CR - Prob. 3CRCh. 4.CR - Prob. 4CRCh. 4.CR - Prob. 5CRCh. 4.CR - Prob. 6CRCh. 4.CR - Prob. 7CRCh. 4.CR - Prob. 8CRCh. 4.CR - Prob. 9CRCh. 4.CR - Prob. 10CRCh. 4.CR - Prob. 11CRCh. 4.CR - Prob. 12CRCh. 4.CR - Prob. 13CRCh. 4.CR - Prob. 14CRCh. 4.CR - Prob. 15CRCh. 4.CR - Prob. 16CRCh. 4.CR - Prob. 17CRCh. 4.CR - Prob. 18CRCh. 4.CR - Prob. 19CRCh. 4.CR - Prob. 20CRCh. 4.CR - Prob. 21CRCh. 4.CR - Prob. 22CRCh. 4.CR - Prob. 23CRCh. 4.CR - Prob. 24CRCh. 4.CR - Prob. 25CR
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