Explanation Procedure used: Solving radical equations: 1. Isolate a single radical on one side of the equation. 2. Square both sides of the equation. (Or raise both sides to a power that is equal to the index of the radical.). 3. If a radica1 remains, repeat steps 1 and 2. 4. Solve the resulting equation. 5. All solutions must be checked in the original equation, and only those that satisfy the original equation are actual solutions. Calculation: By using above procedure, the given equation can be solved as follows. ( 4 x + 5 3 ) 3 = ( x 2 − 7 3 ) 3 [ ∵ Take cube on both sides ] 4 x + 5 = x 2 − 7 − x 2 + 7 + 4 x + 5 = 0 − x 2 + 4 x + 12 = 0 Factorize the above equation to find the value of x

College Algebra in Context with Integrated Review and Worksheets Plus MyLab Math with Pearson eText-- Access Card Package

1st Edition

ISBN: 9780134380155

Author: Ronald J. Harshbarger, Lisa S. Yocco

Publisher: PEARSON

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Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Chapter 4.4, Problem 7E

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To solve: The equation 4x+53=x2−73 algebraically and check the solution graphically or by substitution.

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Chapter 4.4, Problem 6E

Chapter 4.4, Problem 8E

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Chapter 4 Solutions

College Algebra in Context with Integrated Review and Worksheets Plus MyLab Math with Pearson eText-- Access Card Package

Ch. 4.1 - In Exercises 116, (a) sketch the graph of each...Ch. 4.1 - In Exercises 116, (a) sketch the graph of each...Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - In Exercises 116, (a) sketch the graph of each...Ch. 4.1 - Prob. 7E Ch. 4.1 - Prob. 8E Ch. 4.1 - Prob. 9E Ch. 4.1 - Prob. 10E

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The equation 4 x + 5 3 = x 2 − 7 3 algebraically and check the solution graphically or by substitution.

Solution Summary: The author explains the procedure used to solve the equation sqrt[3]4x+5.

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To solve: The equation 4x+53=x2−73 algebraically and check the solution graphically or by substitution.

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Chapter 4 Solutions