Explanation Take a piecewise continuous function f ( x ) , f ( x ) = { 6 x 2 + 4 x + 5 if 0 ≤ x<1 x 2 + 2 x + 3 if 1 ≤ x<2 x + 10 if 2 ≤ x ≤ 3 } Differentiate both sides of the function f ( x ) with respect to x , for 0 ≤ x < 1 . f ′ ( x ) = 12 x + 4 Differentiate both sides of the function f ( x ) with respect to x , for 1 ≤ x < 2 . f ′ ( x ) = 2 x + 2 Differentiate both sides the function f ( x ) with respect to x , for 2 ≤ x ≤ 3 . f ′ ( x ) = 1 Therefore, the derivative of the given function is, f ′ ( x ) = { 12 x + 4 if 0 ≤ x < 1 2 x + 2

Applied Calculus for the Managerial, Life, and Social Sciences

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ISBN: 9781305887831

Author: Tan

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Chapter 4.4, Problem 78E

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Whether the statement “If f is not continuous on the closed interval [a,b] , then f cannot have an absolute maximum value” is true or false.

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Chapter 4.4, Problem 77E

Chapter 4.4, Problem 79E

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Chapter 4 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences

Ch. 4.1 - Explain each of the following: a. f is increasing...Ch. 4.1 - Prob. 2CQ Ch. 4.1 - Prob. 3CQ Ch. 4.1 - Prob. 4CQ Ch. 4.1 - Prob. 5CQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E

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Whether the statement “If f is not continuous on the closed interval [ a , b ] , then f cannot have an absolute maximum value” is true or false.

Solution Summary: The author explains whether the statement "If f is not continuous on the closed interval left[a,bright], then cannot have an absolute maximum value" is true or false.

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Whether the statement “If f is not continuous on the closed interval [a,b] , then f cannot have an absolute maximum value” is true or false.

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Chapter 4 Solutions