Chapter 4.4, Problem 5P

Interpretation Introduction

Interpretation:

The percentage of each enantiomer of limonene and percent enantiomeric excess is to be determined in the sample, which is $\text{95\%}$ enantiopure.

Concept introduction:

The percent enantiomeric excess is the difference between the percent of the major enantiomer and the minor enantiomer.

$\text{\%}\text{Enantiomeric excess}\text{=}\left(\text{\% Major enantiomer}\right)\text{-}\left(\text{\% Minor enantiomer}\right)$

When a sample contains a chiral compound and one enantiomer is present in excess than the other, the sample is optically active.

When all the molecules have the same handedness, it is called enantiopure.