Explanation Given: The equation is log w + log ( 3 w − 13 ) = 1 . Calculation: Apply the product property of logarithm on the left: log w + log ( 3 w − 13 ) = log [ w ( 3 w − 13 ) ] . Thus, the equation becomes log [ w ( 3 w − 13 ) ] = 1 . Exponentiation to the base 10: 10 log [ w ( 3 w − 13 ) ] = 10 1 For positive numbers a and u , with a ≠ 1 , a log a u = u . So, 10 log [ w ( 3 w − 13 ) ] = w ( 3 w − 13 ) . Thus, the equation becomes w ( 3 w − 13 ) = 10

Mathematics With Applications, Loose-leaf Edition Plus Mylab Math With Pearson Etext -- 18-week Access Card Package (12th Edition)

12th Edition

ISBN: 9780135998304

Author: Margaret L. Lial, Tom Hungerford, John P. Holcomb, Bernadette Mullins

Publisher: PEARSON

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Chapter 4.4, Problem 48E

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To calculate: The solution of equation, logw+log(3w−13)=1.

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Chapter 4.4, Problem 47E

Chapter 4.4, Problem 49E

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Mathematics With Applications, Loose-leaf Edition Plus Mylab Math With Pearson Etext -- 18-week Access Card Package (12th Edition)

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The solution of equation, log w + log ( 3 w − 13 ) = 1 .

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