Chapter 4.4, Problem 43E

To determine

To find the LCD

Answer to Problem 43E

  $\frac{5}{12}$ is greater than $\frac{4}{15}$ .

Explanation of Solution

Given information: $\frac{5}{12},\frac{4}{15}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 12 and 15 is 60

So ,denominator of both fractions 60.

  $\frac{5\times 5}{12\times 5}=\frac{25}{60}$

  $\frac{4\times 4}{15\times 4}=\frac{16}{60}$

  $\frac{25}{60}>\frac{16}{60}$

So, $\frac{5}{12}$ is greater than $\frac{4}{15}$ .