The value of the expression ln ( 6 ) by using the properties of logarithm such that ln 2 ≈ 0.6931 and ln 3 ≈ 1.0986 . Also, check the value by using a calculator.
The value of the expression ln ( 6 ) by using the properties of logarithm such that ln 2 ≈ 0.6931 and ln 3 ≈ 1.0986 . Also, check the value by using a calculator.
Solution Summary: The author calculates the value of the expression mathrmln(6) by using the properties of logarithm.
To calculate: The value of the expression ln(6) by using the properties of logarithm such that ln2≈0.6931 and ln3≈1.0986. Also, check the value by using a calculator.
(b)
To determine
To calculate: The value of the expression ln(23) by using the properties of logarithm such that ln2≈0.6931 and ln3≈1.0986. Also, check the value by using a calculator.
(c)
To determine
To calculate: The value of the expression ln(81) by using the properties of logarithm such that ln2≈0.6931 and ln3≈1.0986. Also, check the value by using a calculator.
(d)
To determine
To calculate: The value of the expression ln(3) by using the properties of logarithm such that ln2≈0.6931 and ln3≈1.0986. Also, check the value by using a calculator.
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1
7. Fill in the blanks to write the calculus problem that would result in the following integral (do
not evaluate the interval). Draw a graph representing the problem.
So
π/2
2 2πxcosx dx
Find the volume of the solid obtained when the region under the curve
on the interval
is rotated about the
axis.
38,189
5. Draw a detailed graph to and set up, but do not evaluate, an integral for the volume of the
solid obtained by rotating the region bounded by the curve: y = cos²x_for_ |x|
≤
and the curve y
y =
about the line
x =
=플
2
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Find f(x) and g(x) such that h(x) = (fog)(x) and g(x) = 3 - 5x.
h(x) = (3 –5x)3 – 7(3 −5x)2 + 3(3 −5x) – 1
-
-
-
f(x) = ☐
Chapter 4 Solutions
Calculus: An Applied Approach (Providence College: MTH 109)
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