To find: The dimensions of the maximum volume.
Answer to Problem 32E
The dimensions of the maximum volume are
Explanation of Solution
Given:
The hypotenuse of the triangle is
Calculation:
Let the radius of the base is
Let the volume of the cone is V
For any function
We get that critical points occurs at
For
Volume will be
For maximum volume, the dimensions of the maximum volume is radius
Chapter 4 Solutions
CALCULUS:GRAPHICAL,...,AP ED.-W/ACCESS
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